XStream - unmarshalling - XML中指定的类型不可见

Question

我刚才有一些XStream存储的XML文件,它们包含对RandomAccessSubList的引用,这个类在包级别之外是不可见的,并且没有默认构造函数,所以XStream抛出了这个错误:

com.thoughtworks.xstream.converters.ConversionException: Cannot construct java.util.RandomAccessSubList as it does not have a no-args constructor : Cannot construct java.util.RandomAccessSubList as it does not have a no-args constructor

---- Debugging information ----
message             : Cannot construct java.util.RandomAccessSubList as it does not have a no-args constructor
cause-exception     : com.thoughtworks.xstream.converters.reflection.ObjectAccessException
cause-message       : Cannot construct java.util.RandomAccessSubList as it does not have a no-args constructor*

这是XML:

<customTimes class="java.util.RandomAccessSubList">
  <l class="list">
    <long>1302174300146</long>
    <long>1302174305231</long>
    <long>1302174310312</long>

等等

我不能只为RandomAccessSubList编写一个转换器,因为它在util包之外是不可见的.如何告诉XStream忽略该属性的类,或者如何为我无法引用的类指定转换器？

提前致谢!

Answer 1

我找到了它的底部 - 结果xstream应该处理那个xml(它不需要一个no-args构造函数),问题出现了,因为我使用的是旧版xstream(1.3.1)的jdk 7.请参见http://code.google.com/p/pitestrunner/issues/detail?id=4.回到jdk 6修复了问题(由于各种原因我无法升级).

在我意识到我确实编写了一个适用于RandomAccessSubList的转换器之前,如果有人需要它:

public class RandomAccessSubListConverter extends CollectionConverter {

public RandomAccessSubListConverter(Mapper mapper) {
    super(mapper); 
} 

@Override
public boolean canConvert(Class arg0) {     
    return arg0.getName().equals("java.util.RandomAccessSubList");
}

@Override
public Object unmarshal(HierarchicalStreamReader reader,
        UnmarshallingContext context) {        
    reader.moveDown();
    ArrayList arrayList = new ArrayList();
    populateCollection(reader, context, arrayList);
    reader.moveUp();
    return arrayList;
}

感谢任何为我着想的人!