如何将HashMap保存到共享首选项？

Question

如何在Android中将HashMap保存到共享首选项？

Answer 1

我不建议将复杂对象写入SharedPreference.相反,我会用ObjectOutputStream它写入内部存储器.

File file = new File(getDir("data", MODE_PRIVATE), "map");    
ObjectOutputStream outputStream = new ObjectOutputStream(new FileOutputStream(file));
outputStream.writeObject(map);
outputStream.flush();
outputStream.close();

Answer 2

我用Gson转换HashMap来String,然后将其保存到SharedPrefs

private void hashmaptest()
{
    //create test hashmap
    HashMap<String, String> testHashMap = new HashMap<String, String>();
    testHashMap.put("key1", "value1");
    testHashMap.put("key2", "value2");

    //convert to string using gson
    Gson gson = new Gson();
    String hashMapString = gson.toJson(testHashMap);

    //save in shared prefs
    SharedPreferences prefs = getSharedPreferences("test", MODE_PRIVATE);
    prefs.edit().putString("hashString", hashMapString).apply();

    //get from shared prefs
    String storedHashMapString = prefs.getString("hashString", "oopsDintWork");
    java.lang.reflect.Type type = new TypeToken<HashMap<String, String>>(){}.getType();
    HashMap<String, String> testHashMap2 = gson.fromJson(storedHashMapString, type);

    //use values
    String toastString = testHashMap2.get("key1") + " | " + testHashMap2.get("key2");
    Toast.makeText(this, toastString, Toast.LENGTH_LONG).show();
}

Answer 3

我编写了一段简单的代码来优先保存地图并从首选项加载地图.不需要GSON或Jackson功能.我只使用了一个以String作为键,布尔值作为值的映射.

private void saveMap(Map<String,Boolean> inputMap){
  SharedPreferences pSharedPref = getApplicationContext().getSharedPreferences("MyVariables", Context.MODE_PRIVATE);
  if (pSharedPref != null){
    JSONObject jsonObject = new JSONObject(inputMap);
    String jsonString = jsonObject.toString();
    Editor editor = pSharedPref.edit();
    editor.remove("My_map").commit();
    editor.putString("My_map", jsonString);
    editor.commit();
  }
}

private Map<String,Boolean> loadMap(){
  Map<String,Boolean> outputMap = new HashMap<String,Boolean>();
  SharedPreferences pSharedPref = getApplicationContext().getSharedPreferences("MyVariables", Context.MODE_PRIVATE);
  try{
    if (pSharedPref != null){       
      String jsonString = pSharedPref.getString("My_map", (new JSONObject()).toString());
      JSONObject jsonObject = new JSONObject(jsonString);
      Iterator<String> keysItr = jsonObject.keys();
      while(keysItr.hasNext()) {
        String key = keysItr.next();
        Boolean value = (Boolean) jsonObject.get(key);
        outputMap.put(key, value);
      }
    }
  }catch(Exception e){
    e.printStackTrace();
  }
  return outputMap;
}

Answer 4

Map<String, String> aMap = new HashMap<String, String>();
aMap.put("key1", "val1");
aMap.put("key2", "val2");
aMap.put("Key3", "val3");

SharedPreferences keyValues = getContext().getSharedPreferences("Your_Shared_Prefs"), Context.MODE_PRIVATE);
SharedPreferences.Editor keyValuesEditor = keyValues.edit();

for (String s : aMap.keySet()) {
    keyValuesEditor.putString(s, aMap.get(s));
}

keyValuesEditor.commit();

Answer 5

作为Vinoj John Hosan的回答,我根据数据的关键字修改了答案以允许更多的通用插入,而不是像单个键那样"My_map".

在我的实现中,MyApp是我的Application覆盖类,并且MyApp.getInstance()用于返回context.

public static final String USERDATA = "MyVariables";

private static void saveMap(String key, Map<String,String> inputMap){
    SharedPreferences pSharedPref = MyApp.getInstance().getSharedPreferences(USERDATA, Context.MODE_PRIVATE);
    if (pSharedPref != null){
        JSONObject jsonObject = new JSONObject(inputMap);
        String jsonString = jsonObject.toString();
        SharedPreferences.Editor editor = pSharedPref.edit();
        editor.remove(key).commit();
        editor.putString(key, jsonString);
        editor.commit();
    }
}

private static Map<String,String> loadMap(String key){
    Map<String,String> outputMap = new HashMap<String,String>();
    SharedPreferences pSharedPref = MyApp.getInstance().getSharedPreferences(USERDATA, Context.MODE_PRIVATE);
    try{
        if (pSharedPref != null){
            String jsonString = pSharedPref.getString(key, (new JSONObject()).toString());
            JSONObject jsonObject = new JSONObject(jsonString);
            Iterator<String> keysItr = jsonObject.keys();
            while(keysItr.hasNext()) {
                String k = keysItr.next();
                String v = (String) jsonObject.get(k);
                outputMap.put(k,v);
            }
        }
    }catch(Exception e){
        e.printStackTrace();
    }
    return outputMap;
}

Answer 6

地图 -> 字符串

val jsonString: String  = Gson().toJson(map)
preferences.edit().putString("KEY_MAP_SAVE", jsonString).apply()

字符串 -> 地图

val jsonString: String = preferences.getString("KEY_MAP_SAVE", JSONObject().toString())
val listType = object : TypeToken<Map<String, String>>() {}.type
return Gson().fromJson(jsonString, listType)