删除数据帧中的每第n行

Question

如何删除R中数据帧的每第n行？

Answer 1

您可以创建如下函数

Nth.delete<-function(dataframe, n)dataframe[-(seq(n,to=nrow(dataframe),by=n)),]

我们来试试吧

DF<-data.frame(A=1:15, B=rnorm(15), C=sample(LETTERS,15))
Nth.delete(DF, 3)

Answer 2

如果你想从数据框或向量等获取每个第n列,请使用模数子集...

通过在此处重复集合作为3的模数来选择第n列(根据需要选择第n个)

> x <- c(1,2,3,4,5,6)
> d <- rbind(x,x,x)
> df <- as.data.frame(d, row.names=T)
> c <- 1:ncol(df)
> c
[1] 1 2 3 4 5 6
c%%3   ### nth cycle, here every 3
[1] 1 2 0 1 2 0

#select the every 3rd column of every 3
> df[, c%%3==0]  
  V3 V6
1  3  6
2  3  6
3  3  6

#every first column of every 3
> df[, c%%3==1]
  V1 V4
1  1  4
2  1  4
3  1  4

#every 2nd column of every 3
> df[, c%%3==2]
  V2 V5
1  2  5
2  2  5
3  2  5


#drop the 3rd columns  
> df[, !(c%%3==0)]
  V1 V2 V4 V5
1  1  2  4  5
2  1  2  4  5
3  1  2  4  5

etc ...交换c <-nrow(df)以对行进行子集化

Answer 3

我希望tidyverse使用%%运算符为该问题添加样式方法。

library(dplyr)
df <- data.frame(V1 = seq(26), V2 = letters)
df %>% dplyr::filter(row_number() %% 2 != 0) ## Delete even-rows
df %>% dplyr::filter(row_number() %% 2 != 1) ## Delete odd-rows
df %>% dplyr::filter(row_number() %% 3 != 1) ## Delete every 3rd row starting from 1

当然，您可以使用相同的想法选择第n行。看这里