Boost :: tokenizer逗号分隔(c ++)

Question

对你们来说应该很容易.....

我正在玩使用Boost的tokenizer,我想创建一个逗号分隔的令牌.这是我的代码:

    string s = "this is, , ,  a test";
boost::char_delimiters_separator<char> sep(",");
boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep);


for(boost::tokenizer<>::iterator beg= tok.begin(); beg!=tok.end(); ++beg)
{
    cout << *beg << "\n";
}

我想要的输出是:

This is


 a test

我得到的是:

This
is
,
,
,
a
test

更新

Answer 1

您必须将分隔符分配给tokenizer!

boost::tokenizer<boost::char_delimiters_separator<char>>tok(s, sep);

另外,使用char_separator替换已弃用的char_delimiters_separator:

string s = "this is, , ,  a test";
boost::char_separator<char> sep(",");
boost::tokenizer< boost::char_separator<char> > tok(s, sep);
for(boost::tokenizer< boost::char_separator<char> >::iterator beg = tok.begin(); beg != tok.end(); ++beg)
{
    cout << *beg << "\n";
}

请注意,还有一个模板参数不匹配:输入这样复杂的类型是很好的习惯:所以最终的版本可能是:

string s = "this is, , ,  a test";
boost::char_separator<char> sep(",");
typedef boost::tokenizer< boost::char_separator<char> > t_tokenizer;
t_tokenizer tok(s, sep);
for (t_tokenizer::iterator beg = tok.begin(); beg != tok.end(); ++beg)
{
    cout << *beg << "\n";
}