计算两行之间的时差

Question

我有一个带有StartDate列的表,我想计算两个连续记录之间的时差.

谢谢.

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@ Mark Byers和@ Yahia,我有request table请求表,startdate

requestId    startdate               
1            2011-10-16 13:15:56
2            2011-10-16 13:15:59
3            2011-10-16 13:15:59
4            2011-10-16 13:16:02
5            2011-10-16 13:18:07

我想知道请求1和2,2和3,3和4之间的时差是什么.我知道我需要自己加入桌面,但我没有得到正确的条款.

Answer 1

要实现您的要求,请尝试以下(从OP编辑后更新):

SELECT A.requestid, A.starttime, (B.starttime - A.starttime) AS timedifference
FROM MyTable A INNER JOIN MyTable B ON B.requestid = (A.requestid + 1)
ORDER BY A.requestid ASC

IF requestid不连续,那么你可以使用

SELECT A.requestid, A.starttime, (B.starttime - A.starttime) AS timedifference
FROM MyTable A CROSS JOIN MyTable B
WHERE B.requestid IN (SELECT MIN (C.requestid) FROM MyTable C WHERE C.requestid > A.requestid)
ORDER BY A.requestid ASC

Answer 2

可接受的答案是正确的，但给出了数字的差异。例如，如果我有以下两个时间戳：

2014-06-09 09:48:15
2014-06-09 09:50:11

时差为196。这就是5011-4815。为了获得时差，您可以如下修改脚本：

SELECT A.requestid, A.starttime, TIMESTAMPDIFF(MINUTE,A.starttime,B.starttime) AS timedifference 
FROM MyTable A INNER JOIN MyTable B ON B.requestid = (A.requestid + 1) 
ORDER BY A.requestid ASC