64位的setjmp/longjmp

Met*_*est 0 c linux 64-bit x86

我曾尝试在64位Ubuntu中使用setjmp/longjmp,但它没有正常工作,而它在32位Ubuntu中工作正常.任何想法,发生了什么.以下是代码,我试图执行.

在64位上,它会在longjmp之后返回时挂起.在维基百科关于setcontext的文章中,它说它无法正常使用64位.我们在setjmp中遇到同样的问题吗?事实上,我试图使用setjmp,以避免setcontext的问题,但它似乎在64位上有相同的问题.

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#include <string>
#include <setjmp.h>

#define NOFTHREADS 2

#define DATASIZE        500
#define SETSIZE         (DATASIZE / NOFTHREADS)  

int data[DATASIZE];
pthread_mutex_t sumMutex;
pthread_mutex_t prodMutex;
int sum;
double prod;
static jmp_buf buf;
int jmp_onced[NOFTHREADS+1];

#define lock pthread_mutex_lock
#define unlock pthread_mutex_unlock

void *SumThread( void *pParam )
{
  unsigned int tid = *((unsigned int*)(pParam));
  int si = tid * SETSIZE;
  int i, j, oi, local_sum;
  double local_prod;
  pthread_attr_t attr;

  if ( setjmp(buf) ) 
    printf( "%d: tid %u back! <<<<<<<<<\n", getpid(), tid );
  if ( jmp_onced[tid] )
    goto end_this;

  printf( "%d: >>>>>>>>>>>>> tid %u, starting <<<<<<<<<<<<\n\n", getpid(), tid );

  for( oi = 0; oi < 5; oi++ )
  {
    local_sum = 0;
    local_prod = 1.0;
    for( i = si; i < (si+SETSIZE); i++ )
    {
      local_sum = local_sum + data[i];
      if ( data[i ] )
      local_prod *= 0.005 * data[i];
    }

    lock( &sumMutex );
    sum += local_sum;
    unlock( &sumMutex );

    lock( &prodMutex );
    prod *= local_prod;
    unlock( &prodMutex );
  }

  printf( "%d: !!!!!!!!!!!!!!tid %u done!!!!!!!!!!!!!!\n\n", getpid(), tid );
  jmp_onced[tid] = 1;
  longjmp( buf, 1 );

end_this:
  printf( "%d: ****** tid %u is exiting! ******\n", getpid(), tid ); 
  return 0;
}

void real_main()
{
  pthread_t hThread[NOFTHREADS];
  int index[NOFTHREADS];
  int i, pid, err;
  time_t t1 = time(NULL);

  printf( "%d: Inside real_main, primary thread = %lx!\n", getpid(), pthread_self() );
  for( i = 0; i < NOFTHREADS; i++ )
  {
      index[i] = i;
      pthread_create( &hThread[i], NULL, SumThread, &index[i] ); 
  }
  for( i = 0; i < NOFTHREADS; i++ )
      pthread_join( hThread[i], NULL );

  printf( "Sum of numbers from 1 to %d is %d\n", DATASIZE, sum ); 
  printf( "Prod of numbers from 1 to %d is %g\n", DATASIZE, prod );
  printf( "\n\n[[[[[ %d(child of %d): Time taken = %lu seconds ]]]]]\n\n", getpid(), getppid(), time(NULL) - t1 );
}

int main(int argc, char **argv)
{
  int pid, i, err;

  printf( "size of long is %d\n", sizeof( long ) );

  sumMutex = PTHREAD_MUTEX_INITIALIZER;
  prodMutex = PTHREAD_MUTEX_INITIALIZER;
  printf( "pid = %d, @sumMutex = %lx, @prodMutex = %lx\n", getpid(), (long)&sumMutex, (long)&prodMutex );   

  for( i = 0; i < DATASIZE; i++ )
    data[i] = i+1;

  switch(pid = fork())
  {
  case -1:
    printf("fork failed");
    break;
  case 0: // Child
    printf( "Child pid() = %d\n", getpid() );
    real_main();
    break;
  default:// Leader
    printf( "Parent pid() = %d\n", getpid() );
    real_main();
  }

  printf( "getppid() = %d, getpid() = %d\n", getppid(), getpid() );
  return 0;
}
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Ala*_*kes 5

您需要jmp_buf为每个线程使用单独的.目前你正在重复使用同一个.

  • 是的,一般来说将跳转缓冲区作为静态变量没有多大意义.只需在使用它的函数中将其声明在堆栈中即可. (2认同)