通过AJAX将关联数组传递给PHP

Question

我试图通过AJAX将其传递给PHP脚本:

  var answers={};
  for (x=0; x< allAnswers.length; x++)
   {
       answers.x=new Array();
       answers.x['id']==allAnswers[x]['id'];
       answers.x['val']=$("#field_" + x).val();
   }

   var data={};
   data.id=questions[qId]['id'];
   data['answers']=answers;

   $.post('index.php',data);

PHP设置为print_r($_POST),这是输出:

answers [object Object]

id       3

我做错了什么？

编辑:更改代码以使用数组,即:

  var answers=new Array();
   for (x=0; x< allAnswers.length; x++)
   {
       answers[x]=new Array();
       answers[x]['id']=allAnswers[x]['id'];
       answers[x]['val']=$("#field_" + x).val();
   }
   var data={};
   data.id=questions[qId]['id'];
   data['answers[]']=answers;

   $.post('index.php',data);

给这个print_r:

Array
(
    [id] => 3
    [answers] => Array
        (
            [0] => 
            [1] => 
        )

)

思考？

Answer 1

替换这个:

var answers=new Array();
for (x=0; x< allAnswers.length; x++) {
    answers[x]=new Array();
    answers[x]['id']=allAnswers[x]['id'];
    answers[x]['val']=$("#field_" + x).val();
}

有了这个:

var answers = new Array();
for (x=0; x< allAnswers.length; x++) {
    answers[x] = {};
    answers[x]['id']=allAnswers[x]['id'];
    answers[x]['val']=$("#field_" + x).val();
}

您需要一个对象数组,而不是数组数组.