选择GROUP_CONCAT,GROUP BY,HAVING

Question

我有odd_id的表,我想为不同的ticket_id选择组合.这是我的查询:

SELECT
ticket_id,
GROUP_CONCAT(odd_id) as oddsconcat
FROM ticket_odds
GROUP BY ticket_id

它给了我以下:

'28', '14472510,14472813,14472546,14472855,14472746,14472610,14472647'
'29', '14471149,14471138,14471125,14475603'
'30', '14471823,14471781,14471655,14471865,14471597,14471968,14471739,14471697,14471923'
'31', '14473874,14473814,14473862,14473838,14473790,14473802,14473826,14473850'
'32', '14471588,14472766,14471651,14471777,14471419'
'33', '14472647,14472605,14471650,14471734'
'34', '14471588,14472704,14471817'
'35', '14475279,14474499'
'282', '14472756,14472652,14472813'
'283', '14471588,14472766,14471419,14471777,14471651'
'284', '14474521'
'285', '14474529'
'286', '14474547'
'287', '14471134,14471199,14473636,14471242,14471398,14471237'

但如果我使用有功能,它不会给我结果.显然:它给了我以下内容:

SELECT
ticket_id,
GROUP_CONCAT(odd_id) as oddsconcat
FROM ticket_odds
GROUP BY ticket_id
HAVING oddsconcat = '14475279,14474499'

返回ticket_id 35,每个人都很高兴,代码工作正常,但如果oddsconcat比这个大,它不会返回任何值.对于前:

SELECT
ticket_id,
GROUP_CONCAT(odd_id) as oddsconcat
FROM ticket_odds
GROUP BY ticket_id
HAVING oddsconcat = '14473874,14473814,14473862,14473838,14473790,14473802,14473826,14473850'

Answer 1

我会把它重写为:

SELECT 
ticket_id, 
GROUP_CONCAT(DISTINCT odd_id ORDER BY odd_id ASC) as oddsconcat 
FROM ticket_odds 
GROUP BY ticket_id 
HAVING oddsconcat = .....

现在输出oddsconcat是确定性的,因为消除了重复项并且项目按升序排列.
这应该使匹配更容易.