Mih*_*csu 7 java methods class method-chaining
我发现了一种在Java中调用多个方法的新方法,我并不真正了解背后发生的事情:
public class NutritionFacts {
private final int servingSize;
private final int servings;
private final int calories;
private final int fat;
private final int sodium;
private final int carbohydrate;
public static class Builder {
// Required parameters
private final int servingSize;
private final int servings;
// Optional parameters - initialized to default values
private int calories = 0;
private int fat = 0;
private int carbohydrate = 0;
private int sodium = 0;
public Builder(int servingSize, int servings) {
this.servingSize = servingSize;
this.servings = servings;
}
public Builder calories(int val)
{ calories = val; return this; }
public Builder fat(int val)
{ fat = val; return this; }
public Builder carbohydrate(int val)
{ carbohydrate = val; return this; }
public Builder sodium(int val)
{ sodium = val; return this; }
public NutritionFacts build() {
return new NutritionFacts(this);
}
}
private NutritionFacts(Builder builder) {
servingSize = builder.servingSize;
servings = builder.servings;
calories = builder.calories;
}
}
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现在使用这一行来实例化类,这里让它变得混乱:
NutritionFacts cocaCola = new NutritionFacts.Builder(240, 8).calories(100).sodium(35).carbohydrate(27).build();
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这一切都有意义,直到NutritionFacts.Build(int,int),之后,究竟发生了什么?为什么在calories,sodium,carbohydrate从生成器类方法需要返回this?那个班级的地址在哪里?
谢谢!
Dav*_*ton 11
它没有"进入"任何东西.
这些方法返回一个值.在这种情况下,它们返回当前实例this.那个实例有方法,比如calories()和carbohydrates().
foo.calories(12)返回实例,我们可以调用它的方法:foo.calories(12).sodium(35).
它与构造函数中的"返回值"没有什么不同,隐式定义为新实例.在这种情况下,它是正常的方法,仍然返回一个实例 - 当前的实例.
它与此相同:
Builder foo = new Builder(1, 2); // The "return" value of a ctor is the reference, foo
foo.sodium(10); // Returns foo, but we ignore it
foo.calories(42); // Returns foo, but we ignore it
(foo.sodium(10)).calories(42);
^^^^^^^^^^^^^^^^ foo, with the side effect of setting the sodium value
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