iOS - 以编程方式在TableRow的右侧添加ToggleSwitch

Question

目前我正在向一行的右侧添加一个图标,并在选择该特定行时切换灯光.

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *SimpleTableIdentifier = @"SimpleTableIdentifier";
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:SimpleTableIdentifier];
    ...
    ...
    NSUInteger row = [indexPath row];
    if(row == 3)
    {
        //Draw bulb in row
        cell.accessoryView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"bulb-on.png"]];
            //Instead of image, draw toggle-switch here
    }
    else
        cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
    cell.textLabel.text = [listData objectAtIndex:row];
    return cell;
}

我怎样才能绘制一个可用的切换开关而不是那个图像呢？

Answer 1

属性accessoryView只是一个普通的UIView,所以你可以添加任何子视图:

UISwitch *toggleSwitch = [[UISwitch alloc] init];
cell.accessoryView = [[UIView alloc] initWithFrame:toggleSwitch.frame];
[cell.accessoryView addSubview:toggleSwitch];

PS别忘了释放分配的对象!