vkr*_*rzv 7 c++ boost boost-program-options
我使用boost.program_options库.考虑这个简化的案例.
po::options_description desc("Usage");
desc.add_options()
("uninstall,u", "uninstall program")
("custom,c", po::wvalue<std::wstring>(), "specify custom action");
po::variables_map vm;
po::store(po::parse_command_line(argc, argv, desc), vm);
po::notify(vm);
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我想在这样的命令行上产生错误:
testprog.exe -u c- action1
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注意,用户输入错误"c-"而不是"-c".但解析器将此理解为单个-u选项.我该如何处理这类案件?
我想在这样的命令行上产生错误:
Run Code Online (Sandbox Code Playgroud)testprog.exe -u c- action1
请注意,用户输入了错误的“c-”而不是“-c”。但解析器将其理解为单个 -u 选项。我该如何处理此类情况?
指示program_options
库不接受任何位置参数,您将获得所需的行为
代码&编译:
macmini:stackoverflow samm$ cat po.cc
#include <boost/program_options.hpp>
#include <boost/version.hpp>
#include <iostream>
int
main(int argc, char* argv[])
{
namespace po = boost::program_options;
po::options_description desc("Usage");
desc.add_options()
("uninstall,u", "uninstall program")
("custom,c", po::wvalue<std::wstring>(), "specify custom action")
;
po::variables_map vm;
po::command_line_parser cmd_line( argc, argv );
cmd_line.options( desc );
cmd_line.positional( po::positional_options_description() );
try {
po::store( cmd_line.run(), vm );
po::notify(vm);
} catch ( const std::exception& e ) {
std::cerr << e.what() << std::endl;
return -1;
}
return 0;
}
macmini:stackoverflow samm$ g++ po.cc -I /opt/local/include -L/opt/local/lib -lboost_program_options -Wl,-rpath,/opt/local/lib
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跑步:
macmini:stackoverflow samm$ ./a.out -u c- action1
too many positional options
macmini:stackoverflow samm$ ./a.out -u -c action1
macmini:stackoverflow samm$
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