从php数组中简单更新MySQl表

Question

我正在尝试组合一个执行以下操作的函数:

1. 从表单中检索JSON编码的字符串
2. 将字符串解码为php数组
3. 循环生成的php数组,以获取数组的每个部分的值,以便我可以更新MySql表

这是我到目前为止的功能代码:

public function saveTestimonials() {


    $existing_testimonials_update = $this->post('data');

    $update_array = json_decode($existing_testimonials_update);

    foreach ($update_array as $key => $testimonials) {
         foreach($testimonials as $key => $value) {
            //echo "$key = $value\n";

        }
    }

    $db = Loader::db();
    $sql = "UPDATE testimonials SET name=var, content=var WHERE id=var";
    $db->query($sql);

    $this->redirect('/dashboard/testimonials/');

}

这是存储在$ update_array变量中的数组:

Array
(
[0] => stdClass Object
    (
        [id] => 1
        [name] => Mr. John Doe, Manager, ABC Ltd
        [content] => my content 1.
    )

[1] => stdClass Object
    (
        [id] => 2
        [name] => Mr. Joe Smith, Manager, ABC Industries
        [content] => my content 2.
    )

[2] => stdClass Object
    (
        [id] => 3
        [name] => Mr. Mike Smith, Manager, ABC Industries
        [content] => my content 3.
    )

[3] => stdClass Object
    (
        [id] => 4
        [name] => Ms. Jane Doe, Manager, ABCD Ltd
        [content] => my content 4.
    )

)

我已经完成了第1步和第2步,但我仍然坚持第3步.

我还在学习PHP并且有时会遇到语法困难.我试图独自完成这个工作,并花了几个小时,但似乎无法想象这一个.

非常感谢任何帮助.

Answer 1

foreach ($update_array as $key => $testimonials) {
    $name = mysql_real_escape_string($testimonials->name);
    $content = mysql_real_escape_string($testimonials->content);
    $id = intval($testimonials->id);

    $sql = "UPDATE testimonials SET name='$name', content='$content' WHERE id=$id";
    $result = mysql_query($sql);
    if ($result === FALSE) {
        die(mysql_error());
    }
}