加载ASP.Net MVC JSONResult jQuery DataTables

Question

我正在尝试使用DataTables(http://datatables.net)来处理ASP.Net MVC控制器返回的JsonResult.我一直收到"DataTables警告(表id ='示例'):从第0行的数据源请求未知参数'0'"错误,根据文档意味着它无法找到列.

控制器中返回JsonResult的代码如下所示:

    public JsonResult LoadPhoneNumbers()
    {
        List<PhoneNumber> phoneNumbers = new List<PhoneNumber>();
        PhoneNumber num1 = new PhoneNumber { Number = "555 123 4567", Description = "George" };
        PhoneNumber num2 = new PhoneNumber { Number = "555 765 4321", Description = "Kevin" };
        PhoneNumber num3 = new PhoneNumber { Number = "555 555 4781", Description = "Sam" };

        phoneNumbers.Add(num1);
        phoneNumbers.Add(num2);
        phoneNumbers.Add(num3);

        return Json(phoneNumbers, JsonRequestBehavior.AllowGet);
    }

PhoneNumber只是一个普通的C#类,有2个属性,Number和Description.

检索并加载数据的javascript如下所示:

<script>
$(document).ready(function () {
    $('#example').dataTable({
        "bProcessing": true,
        "sAjaxSource": '/Account/LoadPhoneNumbers/',
        "sAjaxDataProp": ""
    });
});
</script>

而html看起来像:

<table cellpadding="0" cellspacing="0" border="0" class="display" id="example">
<thead>
    <tr>
        <th>
            Number
        </th>
        <th>
            Description
        </th>
    </tr>
</thead>
<tbody>
</tbody>
<tfoot>
</tfoot>
</table>

我故意将sAjaxDataProp设置为空字符串,以便DataTables不查找aaData.即使我在控制器中显式设置了aaData:

return Json(new { aaData = phoneNumbers });

我仍然得到错误.有什么建议吗？

谢谢!

Answer 1

以下对我很有用:

$(function () {
    $('#example').dataTable({
        bProcessing: true,
        sAjaxSource: '@Url.Action("LoadPhoneNumbers", "Home")'
    });
});

我已经删除了该sAjaxDataProp属性.

使用此数据源:

public ActionResult LoadPhoneNumbers()
{
    return Json(new
    {
        aaData = new[] 
        {
            new [] { "Trident", "Internet Explorer 4.0", "Win 95+", "4", "X" },
            new [] { "Gecko", "Firefox 1.5", "Win 98+ / OSX.2+", "1.8", "A" },
            new [] { "Webkit", "iPod Touch / iPhone", "iPod", "420.1", "A" }
        }
    }, JsonRequestBehavior.AllowGet);
}

而对于您的电话示例:

public ActionResult LoadPhoneNumbers()
{
    var phoneNumbers = new List<PhoneNumber>(new[] 
    {
        new PhoneNumber { Number = "555 123 4567", Description = "George" },
        new PhoneNumber { Number = "555 765 4321", Description = "Kevin" },
        new PhoneNumber { Number = "555 555 4781", Description = "Sam" }
    });

    return Json(new
    {
        aaData = phoneNumbers.Select(x => new[] { x.Number, x.Description })
    }, JsonRequestBehavior.AllowGet);
}