Seb*_*ian 5 pivot sql-server-2008
如何使用SQL Server 2008数据透视表查询找到在数据透视表中创建的多个列的最大值?
鉴于:
create table ElectionResults_test
(
Total_Votes int,
Precinct_Name varchar(50),
Candidate_Name varchar(50)
)
insert into ElectionResults_test values (4,'CP01', 'DOUG')
insert into ElectionResults_test values (2,'CP02', 'DOUG')
insert into ElectionResults_test values (2,'CP01', 'LATHE')
insert into ElectionResults_test values (4,'CP02', 'LATHE')
SELECT Precinct_Name as ConsPrecinct_Name, 'DOUG' AS Candidate1, [DOUG] AS NumVotes1,
'LATHE' AS Candidate2, [LATHE] AS NumVotes2, 'Needs Data' as WinningCandidate FROM
(Select Total_Votes, Precinct_Name, Candidate_Name from [ELECTIONRESULTS_test])
as SourceTable pivot (sum(Total_Votes) for Candidate_Name in ([DOUG], [LATHE])) as PivotTable
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上面的select语句具有以下输出:
ConsPrecinct_name Candidate1 NumVotes1 Candidate2 NumVotes2 Winning Candidate
CP01 DOUG 4 LATH 2 Needs Data
CP01 DOUG 2 LATH 4 Needs Data
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目标是使用相应NumVotes字段中投票最多的候选名称填充"获胜候选人"字段.
为了更轻松地处理 8 路比赛,您可以使用CROSS APPLY
and VALUES
,您可能还需要 a GROUP BY
,因为您没有说明如何处理平局(这将为每个获胜者返回多行)
SELECT Precinct_Name AS ConsPrecinct_Name,
'DOUG' AS Candidate1,
[DOUG] AS NumVotes1,
'LATHE' AS Candidate2,
[LATHE] AS NumVotes2,
WinningCandidate.name AS WinningCandidate
FROM (SELECT Total_Votes,
Precinct_Name,
Candidate_Name
FROM ElectionResults_test) AS SourceTable PIVOT (SUM(Total_Votes) FOR
Candidate_Name IN ([DOUG], [LATHE])) AS PivotTable
CROSS APPLY (SELECT CASE
WHEN COUNT(*) = 1 THEN MAX(name)
ELSE 'Tie'
END AS name
FROM (SELECT TOP 1 WITH TIES name
FROM (VALUES('DOUG', [DOUG]),
('LATHE', [LATHE])) Y(name, votes)
ORDER BY votes DESC) T)AS WinningCandidate
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