在抽象类中测试私有方法扩展了另一个

Question

我正在尝试在抽象类中测试私有方法.

我有三个抽象类:

abstract class AbstractClass1 extends AbstractClass2
{
   private function _privateFunction()
    {
        //method's body
    }
}

abstract class AbstractClass2 extends AbstractClass3
{
    public function __construct($param)
    {
        parent::__construct($param)
    }
}

abstract class AbstractClass3
{
    public function __construct($param = array()) 
    {
        //something
    }
}

测试类:

class AbstractClass1Test extends PHPUnit_Framework_TestCase
{
    public function test_privateFunction()
    {
        $stub = $this->getMockForAbstractClass("AbstractClass1");
        $class = new ReflectionClass($stub);
        $method = $class->getMethod("_privateFunction");
        $method->setAccessible(true);

        //some assertings with $method->invoke($stub)
    }
}

测试失败,因为错误:

缺少AbstractClass2 :: __ construct()的参数1,在第190行的/usr/share/php/PHPUnit/Framework/MockObject/Generator.php中调用并定义

AbstractClass2.php

public function __construct($param)

AbstractClass1.php

$classMock = $this->getMockForAbstractClass("AbstractClass1");

Generator.php:190

if ($callOriginalConstructor &&
    !interface_exists($originalClassName, $callAutoload)) {
    if (count($arguments) == 0) {
        <strong>$mockObject = new $mock['mockClassName'];</strong>
    } else {
        $mockClass  = new ReflectionClass($mock['mockClassName']);
        $mockObject = $mockClass->newInstanceArgs($arguments);
    }
} else ...

我错了什么？或者我如何在这种情况下测试我的私人功能？

Answer 1

你需要将一个参数传递给AbstractClass1构造函数.将数组中的构造函数参数作为第二个参数传递给getMockForAbstractClass().

$stub = $this->getMockForAbstractClass("AbstractClass1", array('param'));