将数字转换为整数列表

Question

我如何编写magic下面的功能？

>>> num = 123
>>> lst = magic(num)
>>>
>>> print lst, type(lst)
[1, 2, 3], <type 'list'>

Answer 1

你是这个意思？

num = 1234
lst = [int(i) for i in str(num)]

Answer 2

a = 123456
b = str(a)
c = []

for digit in b:
    c.append (int(digit))

print c

Answer 3

你可以这样做:

>>> num = 123
>>> lst = map(int, str(num))
>>> lst, type(lst)
([1, 2, 3], <type 'list'>)

Answer 4

magic = lambda num: map(int, str(num))

然后就做

magic(12345) 

要么

magic(someInt) #or whatever

Answer 5

>>> from collections import deque
>>> def magic(num):
        digits = deque()
        while True:
            num,r = divmod(num,10)
            digits.appendleft(r)
            if num == 0:
                break
        return list(digits)

>>> magic(123)
[1, 2, 3]

根据我的时间,这个解决方案比字符串方法(magic2)快得多,即使是较小的例子.

>>> def magic2(num):
        return [int(i) for i in str(num)]

时序:

magic

>>> timeit.timeit(setup='from __main__ import magic', stmt='magic(123)')
1.3874572762508706
>>> timeit.timeit(setup='from __main__ import magic', stmt='magic(999999999)')
3.2624468999981673

magic2

>>> timeit.timeit(setup='from __main__ import magic2', stmt='magic2(123)')
3.693756106896217    
>>> timeit.timeit(setup='from __main__ import magic2', stmt='magic2(999999999)')
10.485281719412114

Answer 6

不要使用单词列表作为变量名!它是以数据类型构建的python的名称.

另外,请澄清你的问题.如果您正在寻找创建一个成员列表的方法,请执行以下操作:

a = 123
my_list = [a]

和"pythonizing"Cannonade的答案:

a = 123
my_list = [int(d) for d in str(a)]