Spring Web-Service unmarshalling无法正常工作

Lod*_*ger 8 spring web-services spring-ws

我已经像这样配置了我的WebService:

的applicationContext:

<sws:annotation-driven />    
 <bean class="org.springframework.ws.server.endpoint.mapping.PayloadRootAnnotationMethodEndpointMapping" >
<property name="interceptors">
 <list>
    <bean class="org.springframework.ws.server.endpoint.interceptor.PayloadLoggingInterceptor"/>
</list>
</property>
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注意:Interceptor在启动时加载,但是如果请求进来,则不会写任何内容.

我有一个PersonServiceImpl类,方法是addPersonRequest().如果我使用org.dom4j.Element作为方法参数,一切正常;

@Endpoint
public class PersonServiceImpl {
     @PayloadRoot(namespace = "http://www.example.org/person/schema", localPart = "AddPersonRequest")
     @ResponsePayload
       public AddPersonRequest addPersonRequest(@RequestPayload Element element) {
        System.out.println(element.asXML());
        Person response = new Person();
        response.setId(2);
        response.setFirstName("Mad");
        response.setLastName("Mike");
        return response;
     }
}
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但是,如果我更改我的方法参数,如下所示(因此应该使用spring-ws的自动编组),request.getFirstName()将打印null.(JAXB2在类路径上).

Person-class使用@XMLType和@XMLRootElement注释.

注意:编组工作正常.

@Endpoint
public class PersonServiceImpl {
     @PayloadRoot(namespace = "http://www.example.org/person/schema", localPart = "AddPersonRequest")
     @ResponsePayload
       public AddPersonRequest addPersonRequest(@RequestPayload Person request, SoapHeader header) {
        System.out.println(header.getName());
        System.out.println(request.getFirstName());
        Person response = new Person();
        response.setId(2);
        response.setFirstName("Mad");
        response.setLastName("Mike");
        return response;
     }
}
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Person.java:

@XmlType
@XmlRootElement(namespace="http://www.example.org/person/schema", name="Person")
public class Person implements Serializable {

    private int id;
    private String firstName;
    private String lastName;

    @XmlElement
    public String getFirstName() {
        return firstName;
    }
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    @XmlElement
    public String getLastName() {
        return lastName;
    }
    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    @XmlAttribute
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
}
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通过soapUI发送的测试请求(从wsdl生成):

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sch="http://www.example.org/person/schema"> 
<soapenv:Header/>
<soapenv:Body>

  <sch:AddPersonRequest>

     <sch:Person sch:Id="1">

        <sch:FirstName>firstname</sch:FirstName>

        <sch:LastName>lastname</sch:LastName>

     </sch:Person>

  </sch:AddPersonRequest>

</soapenv:Body>
</soapenv:Envelope>
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Pra*_*nti 2

你提到编组正在工作,我不明白为什么解组不起作用,你是否单独测试过编组和解组?

只是为了确保肥皂请求是好的,您可以添加日志拦截器并打印来自访问 Web 服务的客户端的实际请求,将此代码段添加到您的上下文文件中

  <sws:interceptors>
    <bean class="org.springframework.ws.soap.server.endpoint.interceptor.SoapEnvelopeLoggingInterceptor">
        <property name="logRequest" value="true"></property>
        <property name="logResponse" value="true"></property>
    </bean>
</sws:interceptors>
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您应该看到这样的日志消息,其中包含整个肥皂请求,我正在将来自 saop UI 的日志消息请求添加到

   DEBUG [http-8080-2]:endpoint.interceptor.SoapEnvelopeLoggingInterceptor.logMessage - Request:
    <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sch="http://hoost:port/context/patient/schemas">
      <soapenv:Header/>
         <soapenv:Body>
            <sch:addRequest>
              <sch:patient>
                  <sch:id>?</sch:id>
                     <sch:lastname>Joe</sch:lastname>
                </sch:patient>
             </sch:addRequest>
        </soapenv:Body>
      </soapenv:Envelope>
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答案更新

可能是你的肥皂要求,但不确定

        <sch:FirstName>firstname</sch:FirstName> (this should be)

        <sch:firstName>firstname</sch:firstName>
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另一个更新

例外是由于您定义端点的方式造成的,在您的soap请求(sch:AddPersonRequest)中,您发送的是addPersonRequest而不是Person作为有效负载,因此更改端点以反映这一点,@RequestPayload应该是AddPersonRequest而不是Person

     @PayloadRoot(namespace = "http://www.example.org/person/schema", localPart = "AddPersonRequest")
     @ResponsePayload
      public AddPersonRequest addPersonRequest(@RequestPayload AddPersonRequest request, SoapHeader header) {
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