Cyc*_*one 15 mysql join sql-order-by left-join
这是我的查询:
SELECT `p`.`name` AS 'postauthor', `a`.`name` AS 'authorname',
`fr`.`pid`, `fp`.`post_topic` AS 'threadname', `fr`.`reason`
FROM `z_forum_reports` `fr`
LEFT JOIN `forums` `f` ON (`f`.`id` = `fr`.`pid`)
LEFT JOIN `forums` `fp` ON (`f`.`first_post` = `fp`.`id`)
LEFT JOIN `ps` `p` ON (`p`.`id` = `f`.`author_guid`)
LEFT JOIN `ps` `a` ON (`a`.`account_id` = `fr`.`author`)
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我的问题是这个左连接:
SELECT `a`.`name`, `a`.`level`
[..]
LEFT JOIN `ps` `a` ON (`a`.`account_id` = `fr`.`author`)
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因为,如果a
有很多行,它会像我的情况一样返回:
NAME | LEVEL
Test1 | 1
Test2 | 120
Test3 | 2
Test4 | 1
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我希望它选择a.name
与order
水平desc
和限制1,所以它会更高回报的名字level
在那里(a.account_id = fr.author)
.
希望你能得到我.如果没有,请随时发表评论.
ype*_*eᵀᴹ 34
尝试更换:
LEFT JOIN ps a ON a.account_id = fr.author
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有:
LEFT JOIN ps a
ON a.PrimaryKey --- the Primary Key of ps
= ( SELECT b.PrimaryKey
FROM ps AS b
WHERE b.account_id = fr.author
ORDER BY b.level DESC
LIMIT 1
)
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