如何将参数传递给Ajax.ActionLink的Success Function

Question

我有一个像这样的Ajax.ActionLink:

@Ajax.ActionLink("Load Related Titles",
"AjaxLoadRelated",
"Shared",
new { RelatedComics = c.RelatedComic.RelatedTitles },
new AjaxOptions() { HttpMethod = "Get", UpdateTargetId = "divRelatedTitles", LoadingElementId = "divLoading", OnBegin = "ajaxLoadMoreBegin", OnFailure = "ajaxLoadMoreFailed", OnSuccess = "ajaxLoadMoreSuccess" })

目前我的OnSuccess函数如下所示:

function ajaxLoadMoreSuccess() {
    ...
}

我想向它提出一个论点:

function ajaxLoadMoreSuccess(myArg) {
    ...
}

这可能吗？

提前致谢

Answer 1

这是可能的.mvc ajax不显眼的脚本使用三个参数(对应于jquery ajax完整方法的参数)数据,状态,xhr创建一个匿名函数,并使用jquery ajax完整方法的参数调用该方法.例如:

...OnSuccess = "ajaxLoadMoreSuccess1('hello world')"

要么

...OnSuccess = "ajaxLoadMoreSuccess2(calc(), data, status, xhr)"

<script type="text/javascript">
    function ajaxLoadMoreSuccess1(message) {
        alert(message);
    }

    function ajaxLoadMoreSuccess2(x, data, status, xhr) {
        $('#somespan').text('calc was ' + x + ' and data is ' + data);
    }

    function calc() {
        return 1 + 2;
    }
</script>