UITableViewController为节添加标题

Question

我有一个UITableView有多个部分.每个部分都有一个部分标题(自定义视图)是否有一种简单的方法可以检测到有人选择部分标题？(就像didSelectRowAtIndexPath标题一样？)

Answer 1

这与@rckoenes的答案没有根本的不同,但它确实提供了一种更正统的方式来处理视图上的事件而不是使用隐形按钮.

我宁愿在我的标题视图中添加一个UITapGestureRecognizer,而不是添加不可见的按钮并调整它们的大小:

UITapGestureRecognizer *singleTapRecogniser = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleGesture:)] autorelease];
[singleTapRecogniser setDelegate:self];
singleTapRecogniser.numberOfTouchesRequired = 1;
singleTapRecogniser.numberOfTapsRequired = 1;   
[yourHeaderView addGestureRecognizer:singleTapRecogniser];

然后:

- (void) handleGesture:(UIGestureRecognizer *)gestureRecognizer;

您可以使用gesture.view查看触摸的内容.然后做你需要做的任何事情来找出它是哪个标头(标签,数据阵列查找......)

Answer 2

没有办法做到这一点UITableViewDelegate.

您可以做的是添加一个大小为标题视图大小的按钮并将其添加到视图中.将按钮的标记设置为节索引.然后只需添加UIViewController作为目标UIControlEventTouchUpInside.

然后,通过查看按钮的标签,您可以看到单击了哪个部分.

Answer 3

这适用于评估部分和行。我希望它能帮助其他正在努力使这项工作正常进行的人......

override func viewDidLoad() {
    let tapGesture = UITapGestureRecognizer(target: self, action: #selector(sectionTapped(sender:)))
    tableView?.addGestureRecognizer(tapGesture)
    tapGesture.delegate = self as? UIGestureRecognizerDelegate
}

@objc func sectionTapped(sender: UITapGestureRecognizer) {
    if sender.state == UIGestureRecognizerState.ended {
        guard let tableView = self.tableView else {
            return
        }
        if let view = sender.view {
            let tapLocation = sender.location(in: tableView)
            if let tapIndexPath = tableView.indexPathForRow(at: tapLocation) {              
                if (tableView?.cellForRow(at: tapIndexPath) as? UITableViewCell) != nil {
                    // do something with the row
                    print("tapped on row at index: \(tapIndexPath.row)")
                }
            }  else {
                for i in 0..<tableView.numberOfSections {
                    let sectionHeaderArea = tableView.rectForHeader(inSection: i)
                    if sectionHeaderArea.contains(tapLocation) {
                        // do something with the section
                        print("tapped on section at index: \(i)")
                    }
                }
            }
        }
    }
}

Answer 4

这是在Swift 2中对我有用的东西：

override func tableView(tableView: UITableView, viewForHeaderInSection section: Int) -> UIView? {
    let footerView = UITableViewHeaderFooterView()
    footerView.textLabel?.text = "Header Text"
    let tapRecognizer = UITapGestureRecognizer(target: self, action: #selector(handleTap))
    tapRecognizer.delegate = self
    tapRecognizer.numberOfTapsRequired = 1
    tapRecognizer.numberOfTouchesRequired = 1
    footerView.addGestureRecognizer(tapRecognizer)
    return footerView
}

func handleTap(gestureRecognizer: UIGestureRecognizer) {
    print("Tapped")
}