将 3 个 IEnumerable<Application> 列表合并为一个

Question

我已经简化了我的问题

public class Application
{
    public int Id { get; set; }
    public int Version { get; set; }
    public int Status { get; set; }
}

我的 3 个清单：

IEnumerable<Application> applications1 = new List<Application>
{
    new Application {Id = 1, Version = 1, Status = 1},
    new Application {Id = 2, Version = 1, Status = 1},
    new Application {Id = 3, Version = 3, Status = 1}
};

IEnumerable<Application> applications2 = new List<Application>
{
    new Application {Id = 1, Version = 2, Status = 2},
    new Application {Id = 2, Version = 2, Status = 2},
    new Application {Id = 3, Version = 1, Status = 0}
};

IEnumerable<Application> applications3 = new List<Application>
{
    new Application {Id = 1, Version = 5, Status = 1},
    new Application {Id = 2, Version = 0, Status = 1},
    new Application {Id = 3, Version = 6, Status = 1}
};

我想制作这个：

IEnumerable<Application> applications4 = new List<Application>
{
    new Application {Id = 1, Version = 5, Status = 2},
    new Application {Id = 2, Version = 2, Status = 2},
    new Application {Id = 3, Version = 6, Status = 1}
};

即具有最高 Version 和 Status 值的列表。我尝试过使用 LINQ 但我不明白。

我最好的是这个，但它只是获得最高版本。我不明白当有 2 个属性可供选择时我该怎么做：

IEnumerable<Application> applications4 = applications1
    .Concat(applications2)
    .Concat(applications3)
    .GroupBy(a => a.Id)
    .Select(g => g.Aggregate((acc, curr) => acc.Version > curr.Version ? acc: curr ))
    .ToList();

Answer 1

您应该使用Max()从分组属性中获取最大值。

IEnumerable<Application> applications4 = applications1
    .Concat(applications2)
    .Concat(applications3)
    .GroupBy(a => a.Id)
    .Select(g => new Application
            {
                Id = g.Key,
                Version = g.Max(x => x.Version),
                Status = g.Max(x => x.Status)
            })
    .ToList();