使用AsyncTask在ListView中加载图像

Rod*_*igo 15 android android-listview android-adapter android-asynctask

我有一个可以容纳图像的ListView.这取决于SDCARD中是否存在图像.

这是我的示例代码:

public class MainActivity extends Activity  {

    ListView mListView;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        mListView = new ListView(this);
        setContentView(mListView);

        String[] arr = new String[] { 
                "/example/images/1.jpg", "/example/images/2.jpg",  
                "/example/images/3.jpg", "/example/images/4.jpg",  
                "/example/images/5.jpg", "/example/images/6.jpg", 
                "/example/images/7.jpg", "/example/images/8.jpg",  
                "/example/images/9.jpg", "/example/images/1.jpg", 
                "/example/images/2.jpg", "/example/images/3.jpg",  
                "/example/images/4.jpg", "/example/images/5.jpg",  
                "/example/images/6.jpg", "/example/images/7.jpg",  
                "/example/images/8.jpg", "/example/images/9.jpg", 
                "/example/images/1.jpg", "/example/images/2.jpg",  
                "/example/images/3.jpg", "/example/images/4.jpg",  
                "/example/images/5.jpg", "/example/images/6.jpg", 
                "/example/images/7.jpg", "/example/images/8.jpg",  
                "/example/images/9.jpg", "/example/images/1.jpg", 
                "/example/images/2.jpg", "/example/images/3.jpg",  
                "/example/images/4.jpg", "/example/images/5.jpg",  
                "/example/images/6.jpg", "/example/images/7.jpg",  
                "/example/images/8.jpg", "/example/images/9.jpg"}; 

        List<String> list = Arrays.asList(arr);

        MyAdapter adapter = new MyAdapter(this, R.layout.listitem_imv, list);

        mListView.setAdapter(adapter);
    }

    class MyAdapter extends ArrayAdapter<String>{

        List<String> mList;
        LayoutInflater mInflater;
        int mResource;

        public MyAdapter(Context context, int resource,
                List<String> objects) {
            super(context, resource, objects);

            mResource = resource;
            mInflater = getLayoutInflater();
            mList = objects;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            View view;

            if(convertView == null){
                view = mInflater.inflate(mResource, null);
            }else{
                view = convertView;
            }

            ImageView imageView = (ImageView) view.findViewById(R.id.imv);
            TextView textView = (TextView) view.findViewById(R.id.txv);

                            imageView.setTag(mList.get(position));//tag of imageView == path to image
            new LoadImage().execute(imageView);
            textView.setText(mList.get(position).toString());

            return view;
        }       
    }

    class LoadImage extends AsyncTask<Object, Void, Bitmap>{

        private ImageView imv;
        private String path;


        @Override
        protected Bitmap doInBackground(Object... params) {
            imv = (ImageView)   params[0];

            path = imv.getTag().toString();

            Bitmap bitmap = null;
            File file = new File( 
                    Environment.getExternalStorageDirectory().getAbsolutePath() + path);

            if(file.exists()){
                bitmap = BitmapFactory.decodeFile(file.getAbsolutePath());
            }

            return bitmap;
        }
        @Override
        protected void onPostExecute(Bitmap result) {
            if(result != null && imv != null){
                imv.setVisibility(View.VISIBLE);
                imv.setImageBitmap(result);
            }else{
                imv.setVisibility(View.GONE);
            }
        }
    }
}
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'sdcard/example/images'目录包含图像:1.jpg,2.jpg,3.jpg,4.jpg,6.jpg,7.jpg和9.jpg.预期的结果是: 例

但是,如果我快速滚动列表,一些图像会插入错误的项目中.它发生在getView()方法中使用convertView.

如果我使用以下代码,代码工作正常:

        //if(convertView == null){
        //  view = mInflater.inflate(mResource, null);
        //}else{
        //  view = convertView;
        //}
        view = mInflater.inflate(mResource, null);
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当列表快速滚动时,由于使用了convertView,两个asyncTasks可以引用同一个View.当视图不再可见时,如何取消AsyncTask?(并且由ListView的另一项使用)

编辑

            @Override
    protected void onPostExecute(Bitmap result) {
        if(result != null && imv != null){

            if(imv.getTag().equals(path)){
                imv.setVisibility(View.VISIBLE);
                imv.setImageBitmap(result);
            }else{
                imv.setVisibility(View.GONE);
            }

        }else{
            imv.setVisibility(View.GONE);
        }
    }
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sha*_*chi 41

您可以将ImageView发送到任务构造函数并在那里保留对图像路径的引用.现在在onPostExecute中,检查ImageView的当前标记是否与您开始使用的标记相同.如果是,则设置图像.如果不是,不要做任何事情.

但是,这意味着无论如何都会下载图像.你不会在视图上设置错误的图像.

编辑: 首先将ImageView传递给任务构造函数:

new LoadImage(imageView).execute()
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然后在LoadImage构造函数中保存对ImageView和图像路径的引用.在构造函数中保存路径非常重要,而不是在doInBackground中,以确保我们不会遇到多线程问题.然后在onPostExecute我们检查当前路径.

class LoadImage extends AsyncTask<Object, Void, Bitmap>{

        private ImageView imv;
        private String path;

        public LoadImage(ImageView imv) {
             this.imv = imv;
             this.path = imv.getTag().toString();
        }

    @Override
    protected Bitmap doInBackground(Object... params) {
        Bitmap bitmap = null;
        File file = new File( 
                Environment.getExternalStorageDirectory().getAbsolutePath() + path);

        if(file.exists()){
            bitmap = BitmapFactory.decodeFile(file.getAbsolutePath());
        }

        return bitmap;
    }
    @Override
    protected void onPostExecute(Bitmap result) {
        if (!imv.getTag().toString().equals(path)) {
               /* The path is not same. This means that this
                  image view is handled by some other async task. 
                  We don't do anything and return. */
               return;
        }

        if(result != null && imv != null){
            imv.setVisibility(View.VISIBLE);
            imv.setImageBitmap(result);
        }else{
            imv.setVisibility(View.GONE);
        }
    }

}
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  • @shabyasachi这个解决方案不正确,我不理解upvotes.ListView不像这样工作,它始终使用相同的视图项来显示内容,并且在滚动时,它使用循环视图来显示新项.这个解决方案是错误的. (3认同)

Jef*_*rod 8

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