JavaScript - 获取两个日期之间的分钟数

Question

如果我有两个日期,我如何使用JavaScript在几分钟内获得两个日期之间的差异？

Answer 1

你可以签出这个代码:

var today = new Date();
var Christmas = new Date("12-25-2012");
var diffMs = (Christmas - today); // milliseconds between now & Christmas
var diffDays = Math.floor(diffMs / 86400000); // days
var diffHrs = Math.floor((diffMs % 86400000) / 3600000); // hours
var diffMins = Math.round(((diffMs % 86400000) % 3600000) / 60000); // minutes
alert(diffDays + " days, " + diffHrs + " hours, " + diffMins + " minutes until Christmas 2009 =)");

或者var diffMins = Math.floor((...如果你不想要几分钟就丢弃秒.

Answer 2

减去2个Date对象可以得到毫秒差异,例如:

var diff = Math.abs(new Date('2011/10/09 12:00') - new Date('2011/10/09 00:00'));

Math.abs用于能够使用绝对差异(因此new Date('2011/10/09 00:00') - new Date('2011/10/09 12:00')给出相同的结果).

将结果除以1000可得出秒数.将它除以60可得出分钟数.要舍入到整分钟,请使用Math.floor或Math.ceil:

var minutes = Math.floor((diff/1000)/60);

在此示例中,结果将为720

Answer 3

var startTime = new Date('2012/10/09 12:00'); 
var endTime = new Date('2013/10/09 12:00');
var difference = endTime.getTime() - startTime.getTime(); // This will give difference in milliseconds
var resultInMinutes = Math.round(difference / 60000);

Answer 4

执行此计算的简单函数:

function getMinutesBetweenDates(startDate, endDate) {
    var diff = endDate.getTime() - startDate.getTime();
    return (diff / 60000);
}

Answer 5

这应该以分钟为单位显示两个日期之间的差异.

const currDate = new Date('Tue Feb 13 2018 13:04:58 GMT+0200 (EET)')
const oldDate  = new Date('Tue Feb 13 2018 12:00:58 GMT+0200 (EET)')

(currDate - oldDate) / 60000 # 64.0026

Answer 6

对于那些喜欢小数字的人

const today = new Date();
const endDate = new Date(startDate.setDate(startDate.getDate() + 7));
const days = parseInt((endDate - today) / (1000 * 60 * 60 * 24));
const hours = parseInt(Math.abs(endDate - today) / (1000 * 60 * 60) % 24);
const minutes = parseInt(Math.abs(endDate.getTime() - today.getTime()) / (1000 * 60) % 60);
const seconds = parseInt(Math.abs(endDate.getTime() - today.getTime()) / (1000) % 60); 

Answer 7

使用moment.js可以轻松解决此问题,如下例所示:

var difference = mostDate.diff(minorDate, "minutes");

可以为其他参数更改第二个参数,请参阅moment.js文档.

例如:"天","小时","分钟"等.

http://momentjs.com/docs/

适用于moment.js的CDN可在此处获得:

https://cdnjs.com/libraries/moment.js

谢谢.

编辑:

mostDate和minorDate应该是片刻类型.

Answer 8

您可以执行以下操作：

1. 得到 difference of dates（差异将以毫秒为单位）
2. 转换milliseconds成minutes即ms/1000/60

编码：

let dateOne = new Date("2020-07-10");
let dateTwo = new Date("2020-07-11");

let msDifference =  dateTwo - dateOne;
let minutes = Math.floor(msDifference/1000/60);
console.log("Minutes between two dates =",minutes);