如何获得最大(最小)元素(res.val
和res.pos
)的值以及位置?
thrust::host_vector<float> h_vec(100);
thrust::generate(h_vec.begin(), h_vec.end(), rand);
thrust::device_vector<float> d_vec = h_vec;
T res = -1;
res = thrust::reduce(d_vec.begin(), d_vec.end(), res, thrust::maximum<T>());
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Jar*_*ock 18
不要用thrust::reduce
.使用thrust::max_element
(thrust::min_element
)thrust/extrema.h
:
thrust::host_vector<float> h_vec(100);
thrust::generate(h_vec.begin(), h_vec.end(), rand);
thrust::device_vector<float> d_vec = h_vec;
thrust::device_vector<float>::iterator iter =
thrust::max_element(d_vec.begin(), d_vec.end());
unsigned int position = iter - d_vec.begin();
float max_val = *iter;
std::cout << "The maximum value is " << max_val << " at position " << position << std::endl;
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传递空范围时要小心max_element
- 您将无法安全地取消引用结果.
Jared Hoberock已经圆满地回答了这个问题.我想在下面稍微改变一下,以便在数组被分配cudaMalloc
而不是通过device_vector
容器分配时的常见情况.
我的想法是device_pointer
dev_ptr
围绕cudaMalloc
'ed原始指针,将min_element
(我正在考虑最小值而不是最大值而不失一般性)的输出转换为a device_pointer
min_ptr
然后找到最小值min_ptr[0]
和位置&min_ptr[0] - &dev_ptr[0]
.
#include "cuda_runtime.h"
#include "device_launch_paraMeters.h"
#include <thrust\device_vector.h>
#include <thrust/extrema.h>
/***********************/
/* CUDA ERROR CHECKING */
/***********************/
#define gpuErrchk(ans) { gpuAssert((ans), __FILE__, __LINE__); }
inline void gpuAssert(cudaError_t code, const char *file, int line, bool abort=true)
{
if (code != cudaSuccess)
{
fprintf(stderr,"GPUassert: %s %s %d\n", cudaGetErrorString(code), file, line);
if (abort) exit(code);
}
}
/********/
/* MAIN */
/********/
int main() {
srand(time(NULL));
const int N = 10;
float *h_vec = (float *)malloc(N * sizeof(float));
for (int i=0; i<N; i++) {
h_vec[i] = rand() / (float)(RAND_MAX);
printf("h_vec[%i] = %f\n", i, h_vec[i]);
}
float *d_vec; gpuErrchk(cudaMalloc((void**)&d_vec, N * sizeof(float)));
gpuErrchk(cudaMemcpy(d_vec, h_vec, N * sizeof(float), cudaMemcpyHostToDevice));
thrust::device_ptr<float> dev_ptr = thrust::device_pointer_cast(d_vec);
thrust::device_ptr<float> min_ptr = thrust::min_element(dev_ptr, dev_ptr + N);
float min_value = min_ptr[0];
printf("\nMininum value = %f\n", min_value);
printf("Position = %i\n", &min_ptr[0] - &dev_ptr[0]);
}
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