如何在Yii中指定过滤器中的表名？

Question

有两个表attendee,和group.都有一个gender领域.每位与会者被分配到1个组.我已经CGridView成功显示了与会者的数量,但是当我添加代码来过滤性别时,我收到以下错误.要计算组中与会者的数量,我手动执行联接; 但是联接使得"性别"字段模糊不清.有没有办法在过滤器中指定它应该使用't'或基表？

当我加载视图时,它正常运行; 当我点击排序时gender,它给了我这样的信息:

错误信息

>     Error 500: <h1>CDbException</h1>
>     <p>CDbCommand failed to execute the SQL statement: SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'gender'
> in where clause is ambiguous. The SQL statement executed was: SELECT
> COUNT(*) FROM (SELECT t.*, IFNULL( count(tbl_attendee.id), 0) as
> attendeeCount FROM `tbl_group` `t` LEFT JOIN tbl_attendee ON
> tbl_attendee.group_id = t.id WHERE gender LIKE :ycp0 GROUP BY t.id) sq
> (/Applications/MAMP/htdocs/yiiroot/framework/db/CDbCommand.php:516)</p><pre>#0
> /Applications/MAMP/htdocs/yiiroot/framework/db/CDbCommand.php(411):
> CDbCommand->queryInternal('fetchColumn', 0, Array)

型号代码

$criteria=new CDbCriteria;
$criteria->compare('name',$this->name,true);
$criteria->compare('gender',$this->gender,true);                
$criteria->compare('agegroup',$this->agegroup,true);
$criteria->select = 't.*, IFNULL( count(tbl_attendee.id), 0) as attendeeCount';
$criteria->join = 'LEFT JOIN tbl_attendee ON tbl_attendee.group_id = t.id';
$criteria->group = 't.id';

$sort = new CSort();
$sort->attributes = array(
    'attendeeCount'=>array(
    'asc'=>'attendeeCount ASC',
    'desc'=>'attendeeCount DESC',
    ),
    '*', // add all of the other columns as sortable
);

return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
'sort'=>$sort,
));

查看代码

$this->widget('zii.widgets.grid.CGridView', array(
    'id'=>'group-grid',
    'dataProvider'=>$model->search(),
    'filter'=>$model,
    'columns'=>array(
       'name',
       array(
        'name'=>'gender',
        'value'=>'Group::$genderLabels[$data->gender]',
        'filter'=>Group::$genderLabels, // <-- This is the filter that breaks.
                                        // $genderLabels = array('Female','Male);
    ),

Answer 1

啊! 我知道了.

在模型代码中更改了这一行:

$criteria->compare('gender',$this->gender,true);

至

$criteria->compare('t.gender',$this->gender,true);

在这里找到答案.