mon*_*jbl 3 sql database oracle hierarchical-data
我正在尝试找到一个好的,有效的方式来运行这样的查询:
SELECT *
FROM tableA a
WHERE a.manager IN ( SELECT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob')
OR a.teamLead IN ( SELECT ID
FROM tableB b
CONNECT BY PRIOR b.ID = b.manager_id
START WITH b.ID = 'managerBob')
OR a.creator IN ( SELECT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob')
Run Code Online (Sandbox Code Playgroud)
如您所见,我正在尝试使用多个WHERE子句,但每个子句在等式的右侧使用相同的数据集.如果我使用多个子句,它似乎运行得非常慢,我很确定这是因为Oracle正在运行每个子查询.有没有办法让这样的工作?
SELECT *
FROM tableA a
WHERE a.manager,
a.teamLead,
a.creator in ( SELECT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob')
Run Code Online (Sandbox Code Playgroud)
顺便说一句,我很抱歉,如果这是我可以用谷歌搜索的东西,我不知道该怎么称呼它.
Ton*_*ews 11
子查询因子可能有所帮助:
WITH people AS
( SELECT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob'
)
SELECT *
FROM tableA a
WHERE a.manager IN (SELECT id FROM people)
OR a.teamLead IN (SELECT id FROM people)
OR a.creator IN (SELECT id FROM people)
Run Code Online (Sandbox Code Playgroud)
你可以做:
WITH bob_subordinates AS (
( SELECT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob')
SELECT * FROM tableA a
WHERE a.manager in (select id from bob_subordinates)
OR a.teamlead in (select id from bob_subordinates)
or a.creator in (select id from bob_subordinates)
Run Code Online (Sandbox Code Playgroud)
替代方案(检查DISTINCT的使用:如果表B中的id不是唯一的,那么这不是等价的):
WITH bob_subordinates AS (
( SELECT DISTINCT id
FROM tableB b
CONNECT BY PRIOR b.id = b.manager_id
START WITH b.id = 'managerBob')
SELECT DISTINCT a.*
FROM tableA a JOIN bob_subordinates b ON b.id IN (a.manager, a.teamlead, a.creator);
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
120 次 |
| 最近记录: |