Mar*_*rcx 0 apache-flex actionscript actionscript-3 arraycollection flex4.5
我有两个ArrayCollection,我想将它们合并为一个...
arr1 =
[0] -> month = 07
tot_err = 15
[1] -> month = 08
tot_err = 16
[2] -> month = 09
tot_err = 17
arr2 =
[0] -> month = 07
tot_ok = 5
[1] -> month = 08
tot_ok = 6
[2] -> month = 09
tot_ok = 7
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我想要这个阵列
arr3 =
[0] -> month = 07
tot_err = 15
tot_ok = 5
[1] -> month = 08
tot_err = 16
tot_ok = 6
[2] -> month = 09
tot_err = 17
tot_ok = 7
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我该怎么做?
编辑:
我做了这个解决方案:
private function mergeArrays(a:ArrayCollection, b:ArrayCollection):ArrayCollection
{
for (var i:int=0;i<a.length;i++)
for each(var item:Object in b)
{
if( a[i].month == item.month){
a[i].tot_err = item.tot_err;
}
}
return a;
}
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但是有一个重要的问题,如果array2(b)有一个item.month没有在array1(a)中的值丢失了...
private function mergeArrays(a:ArrayCollection, b:ArrayCollection):ArrayCollection
{
var result:ArrayCollection = new ArrayCollection();
var months:Dictionary = new Dictionary();
for (var i:int = 0; i < a.length; i++)
{
var mergedItem:Object = new Object();
mergedItem.month = a[i].month;
mergedItem.tot_ok = a[i].tot_ok;
mergedItem.tot_err = null;
for (var j:int = 0; j < b.length; j++)
{
if(a[i].month == b[j].month)
{
mergedItem.tot_err = b[j].tot_err;
}
}
month[mergedItem.month] = true;
result.addItem(mergedItem);
}
// so far we have handled all occurrences between a and b,
// now we need to handle the items from b that are left
for each (var bItem:Object in b)
{
mergedItem = new Object();
mergedItem.month = bItem.month;
mergedItem.tot_err = bItem.tot_err;
mergedItem.tot_ok = null;
if (months[mergedItem.month] == null)
{
month[mergedItem.month] = true;
result.addItem(mergedItem);
}
}
return result;
}
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