Len*_*a V 5 sharing uikit ios swift
[![iPhone 上 Instagram 分享错误的屏幕截图][1]][1]我有一个 UIActivityViewController。它可以很好地为 Mail 和 Twitter 创建帖子,并按预期包含图像,但是当选择 Instagram 图标时,我收到警报“无法共享到 Instagram。您只能在 Instagram 应用程序中共享多个照片和视频”,然后它单击“确定”后挂起(Xcode 中没有错误)。
我对错误消息有点困惑?我正在我的 iPhone 上进行测试。
let activityItem1 = ShareableText(title: name)
var activities:[Any] = [ activityItem1 ]
if let aScreenShot = myScreenshot() {
let activityItem2 = ShareableImage(image: aScreenShot)
activities.append(activityItem2)
}
let shareVC = UIActivityViewController(activityItems: activities, applicationActivities: nil)
shareVC.excludedActivityTypes = [ .assignToContact, .airDrop, .addToReadingList ]
self.present(shareVC, animated: true)
class ShareableImage:NSObject, UIActivityItemSource {
let image:UIImage
init(image:UIImage) {
self.image = image
}
func activityViewControllerPlaceholderItem(_ activityViewController: UIActivityViewController) -> Any {
return image
}
func activityViewController(_ activityViewController: UIActivityViewController, thumbnailImageForActivityType activityType: UIActivity.ActivityType?, suggestedSize size: CGSize) -> UIImage? {
let image = UIImage(named: "Icon_CompletedShare")
return image
}
func activityViewController(_ activityViewController: UIActivityViewController, itemForActivityType activityType: UIActivity.ActivityType?) -> Any? {
return image
}
}
class ShareableText:NSObject, UIActivityItemSource {
let title:String
init(title:String) {
self.title = title
}
func activityViewControllerPlaceholderItem(_ activityViewController: UIActivityViewController) -> Any {
return title
}
func activityViewController(_ activityViewController: UIActivityViewController, subjectForActivityType activityType: UIActivity.ActivityType?) -> String {
return title
}
func activityViewController(_ activityViewController: UIActivityViewController, thumbnailImageForActivityType activityType: UIActivity.ActivityType?, suggestedSize size: CGSize) -> UIImage? {
let image = UIImage(named: "Icon_CompletedShare")
return image
}
func activityViewController(_ activityViewController: UIActivityViewController, itemForActivityType activityType: UIActivity.ActivityType?) -> Any? {
return title
}
}```
[1]: https://i.stack.imgur.com/mfgj0.jpg
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