如何通过AppIntents有条件地打开应用程序？

Question

我目前正在创建一个App应该通过 AppIntent 启动的项目。例如，每当我打开Instagram时，它都应该触发 AppIntent，然后由 AppIntent 决定我的应用程序是否应该打开。第一部分已经可以通过 Apple Shortcuts 正常工作。问题是动态打开或不打开我的App. 不幸的是 openAppWhenRun 字段应该是静态的并且不能在运行时计算。

这是到目前为止的 AppIntent：

struct OpenTimeEfficientIntent: AppIntent {
    
    static var title: LocalizedStringResource = "Opens the app conditionally"
    static var openAppWhenRun: Bool = false
    @Parameter(title: "OpenedApp", optionsProvider: Provider())
    var app: String //this is the initially opened app e.g. Instagram (i want to pass it)
    
    @MainActor
    func perform() async throws -> some IntentResult & ProvidesDialog {
        //at this point I want to decide, whether the app should be launched or not
    }
}

只是要说明：我不想决定要打开哪个视图，而是决定是否要打开视图App。

我尝试了什么？

我已经尝试通过 Deeplinks 打开应用程序，这在 iOS 上是不允许的，因为 AppIntent 只是一个后台任务：The App is neither visible nor entitled, so may not perform un-trusted user actions

尝试动态设置openAppWhenRun也不起作用。

对于上下文

该应用程序基本上是一个确认对话框。当我按“否”时，应用程序将关闭并且没有任何反应。当我按“是”时，Instagram 将再次打开。但在这种情况下，我不想再次启动我的应用程序，以防止陷入循环。

Answer 1

如果您采用ForegroundContinuableIntent而不是AppIntent，它将在后台运行，直到您指示它需要在函数中打开您的应用程序perform。这使您可以有条件地决定是否要打开您的应用程序。

@available(iOS 16.4, *)
struct OpenTimeEfficientIntent: ForegroundContinuableIntent {
    
    static var title: LocalizedStringResource = "Opens the app conditionally"
    static var openAppWhenRun: Bool = false

    @Parameter(title: "OpenedApp", optionsProvider: Provider())
    var app: String //this is the initially opened app e.g. Instagram (i want to pass it)
    
    @MainActor
    func perform() async throws -> some IntentResult & ProvidesDialog {
        //at this point you can decide whether the app should be brought to the foreground or not

        // Stop performing the app intent and ask the user to continue to open the app in the foreground
        throw needsToContinueInForegroundError()

        // You can customize the dialog and/or provide a closure to do something in your app after it's opened
        throw needsToContinueInForegroundError("Please continue to open the app.") {
            UIApplication.shared.open(URL(string: "yourapp://deeplinktocontent")!)
        }

        // Or you could ask the user to continue performing the intent in the foreground - if they cancel the intent stops, if they continue the intent execution resumes with the app open
        // This API also accepts an optional dialog and continuation closure
        try await requestToContinueInForeground()
        return .result(dialog: "I opened the app.")
    }

}