发布到HTTPS URL时,Android WebView.postUrl()显示空白屏幕

Question

在我的Android应用程序中,我将数据发送到httpsservlet URL WebView,如下所示

String postData = "fileContents=" + fileCon;
WebView.postUrl(url, EncodingUtils.getBytes(postData, "BASE64"));

上面代码中的URL是一个servlet URL,我必须发布一些数据,然后从那里重定向到其他URL.

当servlet URL正好时,上面的代码工作正常HTTP.但是当更改为时HTTPS,它显示为空白屏幕.

我为android HTTPS问题尝试了以下解决方案:http: //blog.antoine.li/index.php/2010/10/android-trusting-ssl-certificates/

我从onCreate()方法中删除了上面的代码并尝试了以下代码

ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("fileContents", fileCon));
DefaultHttpClient client = new MyHttpClient(getApplicationContext());
try {   
    HttpPost request = new HttpPost(url);
    UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
    request.setEntity(formEntity);
    HttpResponse resp = client.execute(request);
} catch(Exception e){
    e.printStackTrace();
}

现在我可以发布数据,并从那里也重定向.但我仍然看到一个空白的屏幕.

是因为我没有loadUrl或postUrl我看到空白屏幕？

或者我应该将上述代码放在任何方法中WebView？

Answer 1

尝试这个

    ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
    postParameters.add(new BasicNameValuePair("fileContents", fileCon));
    DefaultHttpClient client = new MyHttpClient(getApplicationContext());
try {   
    HttpPost request = new HttpPost(url);
    UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
    request.setEntity(formEntity);
    HttpResponse resp = client.execute(request);

    //Get data
     HttpEntity entity = resp.getEntity();
     InputStream is = entity.getContent();
     String data = convertStreamToString(is);
     browser=(WebView)findViewById(R.id.myWebView);
     browser.loadData(data,"text/html", "UTF-8");
} catch(Exception e){
    e.printStackTrace();
}

输入流转字符串方法：

private static String convertStreamToString(InputStream is) {

BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();

String line = null;
try {
    while ((line = reader.readLine()) != null) {
        sb.append((line + "\n"));
    }
} catch (IOException e) {
    e.printStackTrace();
} finally {
    try {
        is.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}
return sb.toString();

}