hel*_*ios 25 python basehttprequesthandler
我正在使用Python 3.2.2玩一点,想要编写一个简单的Web服务器来远程访问一些数据.这些数据将由Python生成,因此我不想使用SimpleHTTPRequestHandler,因为它是文件服务器,而是我自己的处理程序.
我从互联网上复制了一些例子,但我被卡住了,因为响应输出流拒绝写入正文内容.
这是我的代码:
import http.server
import socketserver
PORT = 8000
class MyHandler(http.server.BaseHTTPRequestHandler):
def do_HEAD(self):
self.send_response(200)
self.send_header("Content-type", "text/html")
self.end_headers()
def do_GET(self):
self.send_response(200)
self.send_header("Content-type", "text/html")
self.end_headers()
print(self.wfile)
self.wfile.write("<html><head><title>Title goes here.</title></head>")
self.wfile.write("<body><p>This is a test.</p>")
# If someone went to "http://something.somewhere.net/foo/bar/",
# then s.path equals "/foo/bar/".
self.wfile.write("<p>You accessed path: %s</p>" % self.path)
self.wfile.write("</body></html>")
self.wfile.close()
try:
server = http.server.HTTPServer(('localhost', PORT), MyHandler)
print('Started http server')
server.serve_forever()
except KeyboardInterrupt:
print('^C received, shutting down server')
server.socket.close()
Run Code Online (Sandbox Code Playgroud)
编写响应正文的正确代码应该是什么?
非常感谢.
编辑:
错误是:
...
File "server.py", line 16, in do_GET
self.wfile.write("<html><head><title>Title goes here.</title></head>")
File "C:\Python32\lib\socket.py", line 297, in write
return self._sock.send(b)
TypeError: 'str' does not support the buffer interface
Run Code Online (Sandbox Code Playgroud)
spi*_*igo 30
在Python3中,字符串与Python 2.x中的字符串不同.使用其中一个将其转换为字节
self.wfile.write(bytes("<html><head><title>Title goes here.</title></head>","utf-8")
Run Code Online (Sandbox Code Playgroud)
要么
self.wfile.write("<html><head><title>Title goes here.</title></head>".encode("utf-8"))
Run Code Online (Sandbox Code Playgroud)