使用BaseHTTPRequestHandler编写响应主体

hel*_*ios 25 python basehttprequesthandler

我正在使用Python 3.2.2玩一点,想要编写一个简单的Web服务器来远程访问一些数据.这些数据将由Python生成,因此我不想使用SimpleHTTPRequestHandler,因为它是文件服务器,而是我自己的处理程序.

我从互联网上复制了一些例子,但我被卡住了,因为响应输出流拒绝写入正文内容.

这是我的代码:

import http.server
import socketserver

PORT = 8000

class MyHandler(http.server.BaseHTTPRequestHandler):
    def do_HEAD(self):
        self.send_response(200)
        self.send_header("Content-type", "text/html")
        self.end_headers()
    def do_GET(self):
        self.send_response(200)
        self.send_header("Content-type", "text/html")
        self.end_headers()
        print(self.wfile)
        self.wfile.write("<html><head><title>Title goes here.</title></head>")
        self.wfile.write("<body><p>This is a test.</p>")
        # If someone went to "http://something.somewhere.net/foo/bar/",
        # then s.path equals "/foo/bar/".
        self.wfile.write("<p>You accessed path: %s</p>" % self.path)
        self.wfile.write("</body></html>")
        self.wfile.close()

try:
    server = http.server.HTTPServer(('localhost', PORT), MyHandler)
    print('Started http server')
    server.serve_forever()
except KeyboardInterrupt:
    print('^C received, shutting down server')
    server.socket.close()
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编写响应正文的正确代码应该是什么?

非常感谢.

编辑:

错误是:

...
  File "server.py", line 16, in do_GET
    self.wfile.write("<html><head><title>Title goes here.</title></head>")
  File "C:\Python32\lib\socket.py", line 297, in write
    return self._sock.send(b)
TypeError: 'str' does not support the buffer interface
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spi*_*igo 30

在Python3中,字符串与Python 2.x中的字符串不同.使用其中一个将其转换为字节

self.wfile.write(bytes("<html><head><title>Title goes here.</title></head>","utf-8") 
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要么

self.wfile.write("<html><head><title>Title goes here.</title></head>".encode("utf-8"))
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  • 我尝试使用Python 3的.encode()字符串转换,但仍然存在错误.您必须删除最后一行:self.wfile.close()因为do_GET将关闭并自行刷新流. (3认同)

Jee*_*enu 6

对于Python 3,在字符串文字前加上b:

self.wfile.write(b"<foo>bar</foo>")
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