在Python中访问元组的元素

Question

我通过tuple_name [0]访问长度为2元组的元素但是python解释器一直给我错误"索引越界"
这里是代码供参考

def full(mask):
    v = True
    for i in mask:
        if i == 0:
            v = False
    return v

def increment(mask, l):
    i = 0
    while (i < l) and (mask[i] == 1):
        mask[i] = 0
        i = i+1
    if i < l:
        mask[i] = 1  

def subset(X,Y):
    s = len(X)
    mask = [0 for i in range(s)]
    yield []
    while not full(mask):
        increment(mask, s)
        i = 0
        yield ([X[i] for i in range(s) if mask[i]] , [Y[i] for i in range(s) if mask[i]])

x = [100,12,32]
y = ['hello','hero','fool']

s = subset(x,y)  # s is generator

for a in s:
    print a[0]   # python gives me error here saying that index out of bounds but it runs fine if i write "print a"

Answer 1

将最后一行更改为简单print a并运行您上面粘贴的确切代码,我得到以下输出:

[]
([100], ['hello'])
([12], ['hero'])
([100, 12], ['hello', 'hero'])
([32], ['fool'])
([100, 32], ['hello', 'fool'])
([12, 32], ['hero', 'fool'])
([100, 12, 32], ['hello', 'hero', 'fool'])

因此,很清楚,第一次迭代是一个空列表,所以并不能有一个元素0.