Python 从更大的二维列表中获取“子”二维列表?

Bro*_*123 0 python grid 2d list

您如何从更大的二维列表中获取二维子列表?

gridx = 10
gridy = 16

grid = [[0]*gridx for i in range(gridy)]
subgrid = None
# I want to get a subgrid given an x,y grid origin (bottom-left) and x,y subgrid size
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joa*_*uin 6

如果您想在 x1、y1、x2、y2 范围内对 2D 列表进行切片,您可以执行以下操作:

def getsubgrid(x1, y1, x2, y2, grid):
    return [item[x1:x2] for item in grid[y1:y2]]
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例如:

grid = [[1, 2, 3, 4, 5, 6, 7, 8, 9],
        [11,12,13,14,15,16,17,18,19],
        [21,22,23,24,25,26,27,28,29],
        [31,32,33,34,35,36,37,38,39],
        [41,42,43,44,45,46,47,48,49],
        [51,52,53,54,55,56,57,58,59]]

print getsubgrid(3,2,5,4,grid)

#prints [[24, 25], [34, 35]]
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