Deb*_*ski 10 scala overloading shadowing
考虑到
object A {
def m(i: Int) = i
val m = (i: Int) => i * 2
}
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一个人得到
scala> A.m(2)
<console>: error: ambiguous reference to overloaded definition,
both value m in object A of type => (Int) => Int
and method m in object A of type (i: Int)Int
match argument types (Int)
A.m(2)
^
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访问 val
可以完成
scala> val fun = A.m
fun: (Int) => Int = <function1>
scala> fun(2)
res: Int = 4
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要么
scala> A.m.apply(2)
res: Int = 4
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但是如何访问def
?
jpa*_*cek 11
这是完全垃圾(请不要在家里这样做),但你可以通过分配A
一个只有第一个的结构类型的变量m
来做到这一点.
val x : { def m(i:Int):Int } = A
x.m(10)
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