scanf()跳过变量

Question

在C中,使用scanf()参数,scanf("%d %*d", &a, &b)行为不同.只为一个变量而不是两个变量输入值!

请解释一下!

scanf("%d %*d", &a, &b);

Answer 1

所述*基本上意味着说明符被忽略(整数被读取,但是未分配).

man scanf的报价:

 *        Suppresses assignment.  The conversion that follows occurs as
          usual, but no pointer is used; the result of the conversion is
          simply discarded.

Answer 2

星号(*)表示将读取格式的值,但不会写入变量.scanf不希望在其参数列表中为该值指定变量指针.你应该写:

scanf("%d %*d",&a);