spa*_*nia 136
如果logcat将长度限制为1000,那么您可以使用String.subString()拆分要记录的字符串并将其记录为碎片.例如:
int maxLogSize = 1000;
for(int i = 0; i <= veryLongString.length() / maxLogSize; i++) {
int start = i * maxLogSize;
int end = (i+1) * maxLogSize;
end = end > veryLongString.length() ? veryLongString.length() : end;
Log.v(TAG, veryLongString.substring(start, end));
}
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jid*_*vah 28
作为spatulamania答案的后续,我写了一个包装类,为你处理这个问题.您只需要更改导入,它将记录所有内容
public class Log {
public static void d(String TAG, String message) {
int maxLogSize = 2000;
for(int i = 0; i <= message.length() / maxLogSize; i++) {
int start = i * maxLogSize;
int end = (i+1) * maxLogSize;
end = end > message.length() ? message.length() : end;
android.util.Log.d(TAG, message.substring(start, end));
}
}
}
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Lar*_*rsH 18
这建立在spatulamania的答案之上,有点简洁,并且最后不会添加空的日志消息:
final int chunkSize = 2048;
for (int i = 0; i < s.length(); i += chunkSize) {
Log.d(TAG, s.substring(i, Math.min(s.length(), i + chunkSize)));
}
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尝试使用这段代码在logcat中显示长消息.
public void logLargeString(String str) {
if(str.length() > 3000) {
Log.i(TAG, str.substring(0, 3000));
logLargeString(str.substring(3000));
} else {
Log.i(TAG, str); // continuation
}
}
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这是带有HttpLoggingInterceptor的OkHttp的执行方式:
public void log(String message) {
// Split by line, then ensure each line can fit into Log's maximum length.
for (int i = 0, length = message.length(); i < length; i++) {
int newline = message.indexOf('\n', i);
newline = newline != -1 ? newline : length;
do {
int end = Math.min(newline, i + MAX_LOG_LENGTH);
Log.d("OkHttp", message.substring(i, end));
i = end;
} while (i < newline);
}
}
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MAX_LOG_LENGTH 是4000。
在这里,它使用Log.d(调试)和硬编码的“ OkHttp”标签。
它在换行符或达到最大长度时拆分日志。
下面的此类是您可以使用的帮助器类(如果您有lambda支持抛出Jack&Jill或retrolambda),则可以在任何日志上执行OkHttp的相同操作:
/**
* Help printing logs splitting text on new line and creating multiple logs for too long texts
*/
public class LogHelper {
private static final int MAX_LOG_LENGTH = 4000;
public static void v(@NonNull String tag, @Nullable String message) {
log(message, line -> Log.v(tag, line));
}
public static void d(@NonNull String tag, @Nullable String message) {
log(message, line -> Log.d(tag, line));
}
public static void i(@NonNull String tag, @Nullable String message) {
log(message, line -> Log.i(tag, line));
}
public static void w(@NonNull String tag, @Nullable String message) {
log(message, line -> Log.w(tag, line));
}
public static void e(@NonNull String tag, @Nullable String message) {
log(message, line -> Log.e(tag, line));
}
public static void v(@NonNull String tag, @Nullable String message, @Nullable Throwable throwable) {
log(message, throwable, line -> Log.v(tag, line));
}
public static void d(@NonNull String tag, @Nullable String message, @Nullable Throwable throwable) {
log(message, throwable, line -> Log.d(tag, line));
}
public static void i(@NonNull String tag, @Nullable String message, @Nullable Throwable throwable) {
log(message, throwable, line -> Log.i(tag, line));
}
public static void w(@NonNull String tag, @Nullable String message, @Nullable Throwable throwable) {
log(message, throwable, line -> Log.w(tag, line));
}
public static void e(@NonNull String tag, @Nullable String message, @Nullable Throwable throwable) {
log(message, throwable, line -> Log.e(tag, line));
}
private static void log(@Nullable String message, @NonNull LogCB callback) {
if (message == null) {
callback.log("null");
return;
}
// Split by line, then ensure each line can fit into Log's maximum length.
for (int i = 0, length = message.length(); i < length; i++) {
int newline = message.indexOf('\n', i);
newline = newline != -1 ? newline : length;
do {
int end = Math.min(newline, i + MAX_LOG_LENGTH);
callback.log(message.substring(i, end));
i = end;
} while (i < newline);
}
}
private static void log(@Nullable String message, @Nullable Throwable throwable, @NonNull LogCB callback) {
if (throwable == null) {
log(message, callback);
return;
}
if (message != null) {
log(message + "\n" + Log.getStackTraceString(throwable), callback);
} else {
log(Log.getStackTraceString(throwable), callback);
}
}
private interface LogCB {
void log(@NonNull String message);
}
}
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通过 Kotlin,我们可以使用 stdlib chunked函数:
fun logUnlimited(tag: String, string: String) {
val maxLogSize = 1000
string.chunked(maxLogSize).forEach { Log.v(tag, it) }
}
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