Springframework构造函数arg

Question

我有一个MainClass有2个变量.我想将这两个值传递给springframework bean类"Test".我如何在applicationContext.xml中定义它,以及如何将这两个变量值传递给bean"Test".

例如:

class MainClass {
       public int var1;
      public int var2;
      public Test test;

   public void setVar1(int var11) {
    var1 = var11;
   }

    public void setVar2(int var22) {
        var2 = var22;
    }

   public static void main(String args[]) {

       ApplicationContext context = 
           new FileSystemXmlApplicationContext("applicationContext.xml");
      Test = context.getBean("test");
   }
  }

------------ TEST类------------

public class Test {

 public Test (int var1, int var2) {}
}

------------- applicationContext.xml -------------

   <bean id="test" class="com.path.test">
       <constructor-arg index="0" type="int" value="????"/>
       <constructor-arg index="1" type="int" value="????"/>
   </bean>

Answer 1

您可以像这样传递值:

<bean id="test" class="com.path.test.Test">
   <constructor-arg index="0" type="int" value="123"/>
   <constructor-arg index="1" type="int" value="456"/>
</bean>

您应该记住将完全限定的类名作为class属性的值.

也就是说,你的Test班级没有坚持其状态.如果你想获得你在你指定的值applicationContext.xml,你应该创建一些成员Test:

public class Test {
    private int v1;
    private int v2;

    public Test (int var1, int var2) {v1 = var1; v2 = var2;}

    public int getVOne() {
        return v1;
    }

    public int getVTwo() {
        return v2;
    }
}

然后,您应该能够在您的main方法中访问这些:

public static void main(String args[]) {

    ApplicationContext context = 
       new FileSystemXmlApplicationContext("applicationContext.xml");
    Test test = context.getBean("test");
    int v1 = test.getVOne();
    int v2 = test.getVTwo();

    System.out.println("V1: " + v1 + " V2: " + v2); //output: V1: 123 V2: 456
}