在评论之间获取内容

Question

希望这个不太棘手......

我试图<!-- itemtemplate -->使用javascript(使用jQuery插件)获得评论之间的上下文.结果必须排除评论.在这种情况下,父级是一个表,但它可以是任何东西,如div

表

<table id="lvList" class="grid1">
    <tr>
        <th>Name </th>
        <th>Number </th>
        <th>Type </th>
        <th>Account Manager </th>
    </tr>
    <!-- itemtemplate -->
    <tr>
        <td><boundfield output="hyperlink" datafield="name" dataurlfields="id" dataurlformat="details/?id={0}" /></td>
        <td><boundfield output="string" datafield="id" /></td>
        <td><boundfield output="string" datafield="type" /></td>
        <td><boundfield output="string" datafield="accmgr" /></td>
    </tr>
    <!-- itemtemplate -->
</table>

DIV

<div id="lvList">
  <!-- itemtemplate -->
     something something something
     <boundfield output="string" datafield="id" />
  <!-- itemtemplate -->
</div>

---

感谢Felix的想法

function GetTemplate(root, name) {
    var output = "";
    var record = false;
    function iterate(node) {
        var children = node.childNodes;
        for (var i = 0; i < children.length; i++) {
            var child = children[i];
            if (child.nodeType === 3 && child.nodeValue.trim() === "") continue;

            if (child.nodeType === 8 && child.nodeValue.trim() === name) {
                if (!record) { record = true; continue; }
                else { break; }
            }

            if (record)
                output += outerHTML(child);
            else {
                if (child.hasChildNodes)
                    iterate(child);
            }
        }
    }
    iterate(root);
    return output;
};
function ClearTemplate (root, name) {
    var record = false;
    function iterate(node) {
        var children = node.childNodes;
        for (var i = children.length - 1; i >= 0; i--) {
            var child = children[i];
            if (child.nodeType === 8 && child.nodeValue.trim() === name) {
                if (!record) { record = true; continue; }
                else { break; }
            }
            if (record)
                node.removeChild(child);
            else {
                if (child.hasChildNodes)
                    iterate(child);
            }
        }
    }
    iterate(root);
};
function InsertInto (root, name, items) {
    function iterate(node) {
        var children = node.childNodes;
        for (var i = 0; i < children.length; i++) {
            var child = children[i];
            if (child.nodeType === 3 && child.nodeValue.trim() === "") continue;
            if (child.nodeType === 8 && child.nodeValue.trim() === name) {
                for (var n = items.length - 1; n >= 0; n--)
                    child.parentNode.insertBefore(items[n], child.nextSibling);
                break;
            }
            if (child.hasChildNodes)
                iterate(child);
        }
    }
    iterate(root);
};
String.prototype.trim = function () {
    return this.replace(/^(\s|&nbsp;|\u00A0)+|(\s|&nbsp;|\u00A0)+$/g, "");
};
function outerHTML(node) {
    return node.outerHTML || 
            (function (n) {
                var div = document.createElement('div');
                div.appendChild(n.cloneNode(true));
                return div.innerHTML;
            })(node);
};

Answer 1

正则表达式和jQuery:想法是迭代所有子节点并检查节点是否是注释节点,如果是,则是否包含某个字符串,例如itemtemplate.

function extract(node, needle) {
    var children = node.childNodes,
        record = false,
        container = document.createDocumentFragment();

    for(var i = 0, l = children.length; i < l; i++) {
        var child = children[i];

        if(child.nodeType === 8 && child.nodeValue === needle) {
            record = !record;
            continue;
        }   

        if(record) {
            container.appendChild(child.cloneNode(true));
        }       
    }
    return container;
}

用法:

var nodes = extract(someParent, ' itemtemplate ');

DEMO

我不知道这是否是适合您情况的最佳解决方案,您不会提供有关上下文的任何信息.