我创建了一个简单的表,其中包含人员的姓名和电子邮件ID.当我给出这样的创建查询时:
"create table contacts (name text not null, email text primary key not null);"
但这不起作用.我在运行时没有出现任何异常或错误,也没有主键正常工作.在使用SQLite浏览器浏览表时,我观察到只有四种数据类型:

是否可以仅对整数应用主键?如果我想要文本字段的主键是什么情况.谢谢.这是我使用的代码:
public class DBAdapter {
public static final String KEY_ROWID = "_id";
public static final String KEY_NAME = "name";
public static final String KEY_EMAIL = "email";
private static final String TAG = "DBAdapter";
private static final String DATABASE_NAME = "MyDB";
private static final String DATABASE_TABLE = "contacts";
private static final int DATABASE_VERSION = 2;
private static final String DATABASE_CREATE =
"create table contacts (_id integer primary key autoincrement, "
+ "name text not null, email text not null);";
private final Context context;
private DatabaseHelper DBHelper;
private SQLiteDatabase db;
public DBAdapter(Context ctx)
{
this.context = ctx;
DBHelper = new DatabaseHelper(context);
}
private static class DatabaseHelper extends SQLiteOpenHelper
{
DatabaseHelper(Context context)
{
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db)
{
try {
db.execSQL(DATABASE_CREATE);
} catch (SQLException e) {
e.printStackTrace();
}
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion)
{
Log.w(TAG, "Upgrading database from version " + oldVersion + " to "
+ newVersion + ", which will destroy all old data");
db.execSQL("DROP TABLE IF EXISTS contacts");
onCreate(db);
}
}
//---opens the database---
public DBAdapter open() throws SQLException
{
db = DBHelper.getWritableDatabase();
return this;
}
//---closes the database---
public void close()
{
DBHelper.close();
}
//---insert a contact into the database---
public long insertContact(String name, String email)
{
ContentValues initialValues = new ContentValues();
initialValues.put(KEY_NAME, name);
initialValues.put(KEY_EMAIL, email);
return db.insert(DATABASE_TABLE, null, initialValues);
}
//---deletes a particular contact---
public boolean deleteContact(long rowId)
{
return db.delete(DATABASE_TABLE, KEY_ROWID + "=" + rowId, null) > 0;
}
//---retrieves all the contacts---
public Cursor getAllContacts()
{
return db.query(DATABASE_TABLE, new String[] {KEY_ROWID, KEY_NAME,
KEY_EMAIL}, null, null, null, null, null);
}
//---retrieves a particular contact---
public Cursor getContact(long rowId) throws SQLException
{
Cursor mCursor =
db.query(true, DATABASE_TABLE, new String[] {KEY_ROWID,
KEY_NAME, KEY_EMAIL}, KEY_ROWID + "=" + rowId, null,
null, null, null, null);
if (mCursor != null) {
mCursor.moveToFirst();
}
return mCursor;
}
//---updates a contact---
public boolean updateContact(long rowId, String name, String email)
{
ContentValues args = new ContentValues();
args.put(KEY_NAME, name);
args.put(KEY_EMAIL, email);
return db.update(DATABASE_TABLE, args, KEY_ROWID + "=" + rowId, null) > 0;
}
}
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Sam*_*uel 19
根据sqlite文档的常见问题,使用主键TEXT作为数据类型应该可行.
我使用了你的查询,就在这里,创建了表格.
CREATE TABLE contacts ( email text primary key not null, name text not null);
INSERT INTO contacts VALUES ('sample@email.com', 'sample')
INSERT INTO contacts VALUES ('people@email.com', 'sample')
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现在这里出了问题.
当我再次跑这个
INSERT INTO contacts VALUES ('sample@email.com', 'sample')
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什么都没发生,没有错误.但它没有更新记录.所以我得出结论数据完整性,但你没有得到任何关于失败的反馈.
Die*_*ano 10
如果无法插入值,SQLiteDatabase.insertOrThrow()应抛出异常.此外它的返回值,以及从一个SQLiteDatabase.insert()就是rowid插入行或-1如果失败.您应该在代码中选择任何这些替代方案.
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