如何使用带连字符的名称访问此对象属性?

Ian*_*Ian 108 php object

我正在使用某人编写的PHP类来与BaseCamp API进行交互.

我正在做的特定调用是检索待办事项列表中的项目,这很好.

我的问题是,我不知道如何只访问todo-items返回的对象的属性.这是返回对象的var_dump:

object(stdClass)[6]
  public 'completed-count' => string '0' (length=1)
  public 'description' => string 'Description String' (length=89)
  public 'id' => string '12345' (length=7)
  public 'milestone-id' => string '' (length=0)
  public 'name' => string 'Error Reports' (length=13)
  public 'position' => string '1' (length=1)
  public 'private' => string 'false' (length=5)
  public 'project-id' => string '58904' (length=7)
  public 'tracked' => string 'false' (length=5)
  public 'uncompleted-count' => string '1' (length=1)
  public 'todo-items' => 
    object(stdClass)[3]
      public 'todo-item' => 
        object(stdClass)[5]
          public 'completed' => string 'false' (length=5)
          public 'content' => string 'content string here' (length=133)
          public 'created-on' => string '2009-04-16T20:33:31Z' (length=20)
          public 'creator-id' => string '23423' (length=7)
          public 'id' => string '234' (length=8)
          public 'position' => string '1' (length=1)
          public 'responsible-party-id' => string '2844499' (length=7)
          public 'responsible-party-type' => string 'Person' (length=6)
          public 'todo-list-id' => string '234234' (length=7)
  public 'complete' => string 'false' (length=5)
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如何访问todo-items此对象的部分?

Ali*_*man 241

<?php
$x = new StdClass();
$x->{'todo-list'} = 'fred';
var_dump($x);
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所以,$ object - > {'todo-list'}是子对象.如果您可以这样设置,那么您也可以以相同的方式阅读它.

如果你想将它转换为一个数组,这可能会更容易(即明显的$ ret ['todo-list']访问),这个代码几乎是从Zend_Config逐字逐句获取并将为你转换.

public function toArray()
{
    $array = array();
    foreach ($this->_data as $key => $value) {
        if ($value instanceof StdClass) {
            $array[$key] = $value->toArray();
        } else {
            $array[$key] = $value;
        }
    }
    return $array;
}
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  • 虽然这很短而且很甜(以及我推荐的),你也可以通过变量来做到这一点:`$ todolist ='todo-list'; $ X - > $ todolist` (24认同)
  • @Christian 非常好!但是试试 $x-&gt;{$todolist} (2认同)

小智 26

试试这个最简单的方法!

$obj = $myobject->{'mydash-value'};
$objToArray = array($obj);
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  • 代码示例附带好的答案,并为将来的读者提供解释.虽然提出这个问题的人可能理解你的答案,但解释你如何达到这个问题可以帮助无数其他人. (3认同)
  • 哦,这是真正的答案.我试图永远使用'.'访问对象属性名称.在它,这清理了就好了! (2认同)