id lat long speed date address
1 22.92138131 72.44103313 3.96 km/h 2011-09-26 National, Gujarat, India
2 22.92138145 72.44103413 13.96 km/h 2011-09-26 National, Gujarat, India
3 22.92138134 72.44103423 15.96 km/h 2011-09-26 National, Gujarat, India
4 22.92138454 72.44103233 13.96 km/h 2011-09-26 10t ring Rd, Nehru Nagar
5 22.92138354 72.44102533 13.96 km/h 2011-09-26 Anandnagar Rd, Ahmedabad
6 22.92138484 72.44103293 19.96 km/h 2011-09-26 Anandnagar Rd, Ahmedabad
Run Code Online (Sandbox Code Playgroud)
我想写一个查询,以便我的结果如下所示:
id lat long speed date address
1 22.92138131 72.44103313 3.96 km/h 2011-09-26 National, Gujarat, India
4 22.92138454 72.44103233 13.96 km/h 2011-09-26 10t ring Rd, Nehru Nagar
5 22.92138354 72.44102533 13.96 km/h 2011-09-26 Anandnagar Rd, Ahmedabad
Run Code Online (Sandbox Code Playgroud)
我想根据地址删除重复的行.
要检查要删除的内容:
SELECT distinct t1.*
FROM yourtable as t1
join yourtable as t2
WHERE t1.address = t2.address
and t1.id < t2.id
Run Code Online (Sandbox Code Playgroud)
如果你对此感到满意:
DELETE t1
FROM yourtable as t1
join yourtable as t2
WHERE t1.address = t2.address
and t1.id < t2.id
Run Code Online (Sandbox Code Playgroud)
这样您就可以在id列上保留记录的最大值
假设您希望返回 ID 值最小的行:
SELECT
*
FROM
TABLENAME T INNER JOIN
(
SELECT MIN(ID) AS ID FROM TableName
GROUP BY Address
) SUB ON T.ID = SUB.ID
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
13927 次 |
| 最近记录: |