我想根据时间范围使用shell脚本(bash)从日志文件中提取信息.日志文件中的一行如下所示:
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200] "GET / HTTP/1.1" 200 123 "" "Mozilla/5.0 (compatible; Konqueror/2.2.2-2; Linux)"
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我想提取特定数据的间隔.例如,我只需要查看上次记录的数据中最后X分钟或X天前发生的事件.我是shell脚本的新手,但我尝试使用grep命令.
ych*_*che 41
你可以用sed它.例如:
$ sed -n '/Feb 23 13:55/,/Feb 23 14:00/p' /var/log/mail.log
Feb 23 13:55:01 messagerie postfix/smtpd[20964]: connect from localhost[127.0.0.1]
Feb 23 13:55:01 messagerie postfix/smtpd[20964]: lost connection after CONNECT from localhost[127.0.0.1]
Feb 23 13:55:01 messagerie postfix/smtpd[20964]: disconnect from localhost[127.0.0.1]
Feb 23 13:55:01 messagerie pop3d: Connection, ip=[::ffff:127.0.0.1]
...
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所述-n开关告诉sed不输出在读取文件(默认行为)的每一行.
p正则表达式之后的最后一个表示打印与前一个表达式匹配的行.
表达式'/pattern1/,/pattern2/'将打印第一个模式和第二个模式之间的所有内容.在这种情况下,它将打印它在字符串Feb 23 13:55和字符串之间找到的每一行Feb 23 14:00.
zta*_*013 29
使用grep和正则表达式,例如,如果您需要4分钟的日志间隔:
grep "31/Mar/2002:19:3[1-5]" logfile
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将在2002年3月31日19:31和19:35之间返回所有日志行.假设您需要从2011年9月27日开始的最后5天,您可以使用以下内容:
grep "2[3-7]/Sep/2011" logfile
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好吧,我花了一些时间在你的日期格式.....
然而,最后我解决了..
让我们拿一个示例文件(名为logFile),我做了一点简短.比如,你想在这个文件中获得最后5分钟的登录:
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:20:41 +0200] "GET
### lines below are what you want (5 mins till the last record)
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:27:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200] "GET
172.16.0.3 - - [31/Mar/2002:19:30:41 +0200] "GET
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这是解决方案:
# this variable you could customize, important is convert to seconds.
# e.g 5days=$((5*24*3600))
x=$((5*60)) #here we take 5 mins as example
# this line get the timestamp in seconds of last line of your logfile
last=$(tail -n1 logFile|awk -F'[][]' '{ gsub(/\//," ",$2); sub(/:/," ",$2); "date +%s -d \""$2"\""|getline d; print d;}' )
#this awk will give you lines you needs:
awk -F'[][]' -v last=$last -v x=$x '{ gsub(/\//," ",$2); sub(/:/," ",$2); "date +%s -d \""$2"\""|getline d; if (last-d<=x)print $0 }' logFile
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输出:
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:27:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:30:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:30:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:30:41 +0200 "GET
172.16.0.3 - - 31 Mar 2002 19:30:41 +0200 "GET
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编辑
你可能会注意到在输出中[和]消失了.如果你确实想要它们,你可以改变最后一个awk行print $0- >print $1 "[" $2 "]" $3
nic*_*ick -1
您可以使用它来获取当前时间和日志时间:
#!/bin/bash
log="log_file_name"
while read line
do
current_hours=`date | awk 'BEGIN{FS="[ :]+"}; {print $4}'`
current_minutes=`date | awk 'BEGIN{FS="[ :]+"}; {print $5}'`
current_seconds=`date | awk 'BEGIN{FS="[ :]+"}; {print $6}'`
log_file_hours=`echo $line | awk 'BEGIN{FS="[ [/:]+"}; {print $7}'`
log_file_minutes=`echo $line | awk 'BEGIN{FS="[ [/:]+"}; {print $8}'`
log_file_seconds=`echo $line | awk 'BEGIN{FS="[ [/:]+"}; {print $9}'`
done < $log
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并比较log_file_*和current_*变量。