如何正确地将JSON字符串反序列化为包含另一个类的嵌套List的类

Question

我有以下对象图,我使用Jquery的$ .Ajax()将这个相同的"View"对象以JSON(字符串化)从浏览器发送到ASP.Net上的Page方法.JAvascript反序列化适用于View类中的所有字符串和int,但My List<DataItem>为空.

我尝试过:使用chrome dev工具,我使用了字符串化的JSON,创建了一个单元测试并使用了DataContractJsonSerializer和JavaScriptSerializer.该DataContractJsonSerializer对象正确地反序列化了我的对象图,但JavaScriptSerializer转储了我的列表.如何在页面方法上获得正确的反序列化？

public class View
{
    public string Text { get; set; }
    public string AnotherText { get; set; }
    public Int SomeInt { get; set; }
    public List<DataItem> { get; set; }
}

public class DataItem
{
    public Person person {get;set}
}

public class Person
{
    public int Age {get;set}
}

   var dataa = {mqvm: mqvmJSON };
    $.ajax({
        type: "POST",
        dataType: "json",
        contentType: "application/json; charset=utf-8",
        data: JSON.stringify( dataa ),
        url: "GoHere.aspx/WebMethodName",
        success: function(data) {
            alert(data.d);
        },
        error: function(jqXHR, textStatus, errorThrown) {
            alert(jqXHR.responseText + ' ' + errorThrown);
        }
    });

而不是这个(视图obj作为参数).

    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    [WebMethod]
    public static string CreateResponseReview(View mqvm)
    { 
        return "Success";
    }

我怎么能得到这个？(字符串参数)

    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    [WebMethod]
    public static string CreateResponseReview(string mqvm)
    { 
        //do manual JSON deserialization here.

        return "Success";
    }

我的JSON看起来像这样.

    {
    "Text": "6",
    "AnotherText":"wow"
    "SomeInt": 5,
    "DataItem":[
        {
            "person":{
                "Age":23
            }
        },
        {
            "person":{
                "Age":42
            }
        }
    ]
}

Answer 1

我想到了.

我不想使用JavascriptSerializer类,因为它转储了我的嵌套列表,因此我强制它将对象作为字符串传递给我,然后我手动反序列化它.我也一直得到"没有为u0027system.string u0027的类型定义无参数构造函数"

请记住,U0027是一个撇号,因此运行时可能会认为存在名为"System.string"的实际类型而不是System.string.我的问题是 - 我没有正确划分下面名为data2的项目中的参数.我不得不在键和值周围加上"滴答声".

function requestHtmlFromServer(mqvmJSON) {
    var mqvmstring = JSON.stringify(mqvmJSON);
    var data2 = "{\'mqvm\':\'" + mqvmstring + "\' }"; \\<--the problem
    $.ajax({
        type: "POST",
        dataType: "json",
        contentType: "application/json; charset=utf-8",
        data: data2,
        url: "MedicalInformation.aspx/CreateResponseReview",
        success: function(data) {
            alert(data.d);
        },
        error: function(jqXHR, textStatus, errorThrown) {
            alert(jqXHR.responseText + ' ' + errorThrown);
        }
    });
}


    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    [WebMethod]
    public static string CreateResponseReview(string mqvm)
    {
        string noNewLines = mqvm.Replace("\n", "");
        View viewModel = ToObjectFromJSON<View>(noNewLines);
        //do my other stuff here

        return "Success";
    }
    public static T ToObjectFromJSON<T>(string jsonString)
    {
        var serializer = new DataContractJsonSerializer(typeof(T));
        var memoryStream = new MemoryStream(Encoding.Unicode.GetBytes(jsonString));
        var newObject = (T)serializer.ReadObject(memoryStream);
        memoryStream.Close();
        return newObject;
    }

Answer 2

尝试使用以下内容:

反序列化代码

string json = "{\"text\":\"some text\",\"anotherText\":\"some more text\", \"someInt\":1, \"dataItems\":[{\"person\":{age:25}},{\"person\":{age:20}}]}";

JavaScriptSerializer serializer = new JavaScriptSerializer();
View view = serializer.Deserialize<View>(json);

类

public class View
{
    public string Text { get; set; }
    public string AnotherText { get; set; }
    public int SomeInt { get; set; }
    public List<DataItem> DataItems { get; set; }
}

public class DataItem
{
    public Person person { get; set; }
}

public class Person
{
    public int Age {get;set;}
}

JSON

{
    "text":"some text",
    "anotherText":"some more text", 
    "someInt":1, 
    "dataItems":
        [
            {"person":{age:25}},
            {"person":{age:20}}
        ]
}