Kre*_*voL 3 python browser certificate web-scraping selenium-webdriver
我正在尝试在 Python 中执行一个 selenium 程序,以便通过单击当前主页中的按钮转到新的 URL。我是硒的新手,任何有关这方面的帮助将不胜感激。这是我的代码
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
url = 'https://nmit.ac.in'
driver = webdriver.Chrome()
driver.get(url)
try:
# wait 10 seconds before looking for element
element = WebDriverWait(driver, 10).until(
EC.presence_of_element_located(By.LINK_TEXT, "Parent Portal")
)
except:
print()
driver.find_element(By.LINK_TEXT, "Parent Portal").click()
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我花了很多时间寻找解决方案,然后在这里找到了它。
options = webdriver.ChromeOptions()
options.add_experimental_option('excludeSwitches', ['enable-logging'])
driver = webdriver.Chrome(
service= Service(chromedriver_path),
options=options,
)
driver.get('https://www.google.com/')
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它应该消除 selenium 中所有烦人的错误和警告