MVC - 使用Ajax渲染局部视图

Mal*_*olm 11 ajax asp.net-mvc asp.net-mvc-partialview

我在MVC应用程序中有这个标记.

<div id="ingredientlistdiv">
    <% Recipe recipe = (Recipe)Model; %>
    <% Html.RenderPartial("IngredientsListControl", recipe.Ingredients); %>
</div>

<div id="ingrediententrydiv" align="left">
    <% using (Ajax.BeginForm("Add Ingredient", "Recipes/UpdateStep2", new AjaxOptions { UpdateTargetId = "ingredientlistdiv" }))
       { %>
    <p>
        <label for="Units">Units:</label><br />
        <%= Html.TextBox("Units", 0)%>
        <%= Html.ValidationMessage("Units", "*")%>
    </p>
    <p>
        <label for="Measure">Measure:</label><br />
        <%= Html.TextBox("Measure")%>
        <%= Html.ValidationMessage("Measure", "*")%>
    </p>
    <p>
        <label for="IngredientName">Ingredient Name:</label><br />
        <%= Html.TextBox("IngredientName")%>
        <%= Html.ValidationMessage("IngredientName", "*")%>
    </p>
    <p><a href="javascript:document.forms[0].submit()">Save Ingredient</a></p>
    <%= Html.Hidden("RecipeID", recipe.RecipeID.ToString())%>
    <% } %>
</div>
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当这运行时,IngredientsListControl.ascx在浏览器中显示一个新页面,并且不会更新ingredientlistdiv.

这是我的控制器动作

[AcceptVerbs(HttpVerbs.Post)]
        public ActionResult UpdateStep2(FormCollection form)
        {
            var factory = SessionFactoryCreator.Create();

            using (var session = factory.OpenSession())
            {
                Recipe recipe = GetRecipe(session, Convert.ToInt32(form["RecipeID"]));

                Ingredient ingredient = new Ingredient();

                ingredient.UpdateFromForm(form);
                ingredient.Validate(ViewData);

                if (ViewData.ModelState.Count == 0)
                {
                    recipe.Ingredients.Add(ingredient);
                    session.Save(recipe);
                    return PartialView("IngredientsListControl", recipe.Ingredients);
                }


                return Content("Error");
            }
        }
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我在这条线上做得对吗?

return PartialView("IngredientsListControl", recipe.Ingredients);
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这是我如何将控件渲染到div中,因此它不会加载新页面.???

马尔科姆

Ale*_*x42 8

当你使用这个:

<a href="javascript:document.forms[0].submit()">
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......你应该知道它与它不一样

<input type="submit" />
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它不会引发onsubmit事件,也不会调用MVC的AJAX事件处理程序.

要确认这是问题,请添加

<input type="submit" /> 
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在表单内部并尝试一下.

最后,只需从链接中调用onsubmit()即可

<a href="#" onclick="document.forms[0].onsubmit()">
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