如何在C#中shell执行文件？

Question

我一如既往地尝试使用Process类,但是没有用.我所做的就是尝试运行Python文件,就像有人双击它一样.

可能吗？

编辑:

示例代码:

string pythonScript = @"C:\callme.py";

string workDir = System.IO.Path.GetDirectoryName ( pythonScript );

Process proc = new Process ( );
proc.StartInfo.WorkingDirectory = workDir;
proc.StartInfo.UseShellExecute = true;
proc.StartInfo.FileName = pythonScript;
proc.StartInfo.Arguments = "1, 2, 3";

我没有收到任何错误,但脚本没有运行.当我手动运行脚本时,我看到了结果.

Answer 1

这是我从C#执行python脚本的代码,带有重定向的标准输入和输出(我通过标准输入传递信息),从某个地方的Web上的示例复制.Python位置是硬编码的,你可以看到,可以重构.

    private static string CallPython(string script, string pyArgs, string workingDirectory, string[] standardInput)
    {

        ProcessStartInfo startInfo;
        Process process;

        string ret = "";
        try
        {

            startInfo = new ProcessStartInfo(@"c:\python25\python.exe");
            startInfo.WorkingDirectory = workingDirectory;
            if (pyArgs.Length != 0)
                startInfo.Arguments = script + " " + pyArgs;
            else
                startInfo.Arguments = script;
            startInfo.UseShellExecute = false;
            startInfo.CreateNoWindow = true;
            startInfo.RedirectStandardOutput = true;
            startInfo.RedirectStandardError = true;
            startInfo.RedirectStandardInput = true;

            process = new Process();
            process.StartInfo = startInfo;


            process.Start();

            // write to standard input
            foreach (string si in standardInput)
            {
                process.StandardInput.WriteLine(si);
            }

            string s;
            while ((s = process.StandardError.ReadLine()) != null)
            {
                ret += s;
                throw new System.Exception(ret);
            }

            while ((s = process.StandardOutput.ReadLine()) != null)
            {
                ret += s;
            }

            return ret;

        }
        catch (System.Exception ex)
        {
            string problem = ex.Message;
            return problem;
        }

    }

Answer 2

Process.Start应该工作.如果没有,你会发布你的代码和你得到的错误？