DateTime SQL问题

Jay*_*Jay 5 c# sql datetime

我正在尝试让我的代码检查是否已经为今天的日期输入了一个数字.原因是整个书中的docketnumbers重复,有点像抽奖券.我不希望在同一天多次将相同的数字输入数据库.

现在是我的代码

string thisday = DateTime.Now.ToString("MM/dd/yyyy");
Run Code Online (Sandbox Code Playgroud)

然后检查

 public void button11_Click(object sender, EventArgs e)
    {
        string thisday = DateTime.Now.ToString("MM/dd/yyyy");
        errorProvider1.Clear();
        Data.docnum = txtDisplay.Text;
        if (txtDisplay.Text == "")
        {
            errorProvider1.SetError(txtDisplay, "Enter Docket Number");
            return;
        }
        using (var db = new DocketsDataContext())
        {
             var docketCheck = from q in db.Dockets where q.Status== "Ca"  select q;   
             string message = "";
             foreach (var d in docketCheck)
             {
                 message += String.Format(" DocketNum {0} - Status {1} - TimeRaised {2} - Thisday {3}\r\n", d.DocketNum, d.Status, d.TimeRaised, thisday);
             }
             MessageBox.Show(message);


            var complete = from q in db.Dockets
                           where q.DocketNum == txtDisplay.Text && q.Status.Equals("CL") //&& q.TimeRaised.Contains(thisday)
                           select q;

            var cancelcheck = from q in db.Dockets
                              where q.DocketNum == txtDisplay.Text && q.Status.Equals("Ca") && q.TimeRaised.Equals(thisday)
                              select q;

            var docketcheck = from q in db.Dockets
                              where q.DocketNum == txtDisplay.Text && q.Status.Equals("O") //&& q.TimeRaised.Contains(thisday)
                              select q;

            var statuscheck = from q in db.Dockets
                              where q.DocketNum == txtDisplay.Text &&  q.Status.Equals("Ea") //&& q.TimeRaised.Contains(thisday)
                              select q;


            if (cancelcheck.Count() >= 1)
            {
                MessageBox.Show(@"Match Found");
                txtDisplay.Clear();
                txtDisplay.ReadOnly = false;
                var cancel = new Cancel();
                cancel.ShowDialog(this);
            }

            else if (complete.Count() >= 1)
            {
                txtDisplay.Clear();
                txtDisplay.ReadOnly = false;
                var cat = new Docerror();
                cat.ShowDialog(this);
            }

            else if (statuscheck.Count() >= 1)
            {
                txtDisplay.Clear();
                txtDisplay.ReadOnly = false;
                var cat = new Category();
                cat.ShowDialog(this);
            }

            else if (docketcheck.Count() >= 1)
            {
                txtDisplay.Clear();
                txtDisplay.ReadOnly = false;
                var engs = new EngStart();
                engs.ShowDialog(this);
            }

            else
            {

                var sub = new machinesel();
                txtDisplay.Clear();
                sub.ShowDialog(this);
            }
        }

    }
Run Code Online (Sandbox Code Playgroud)

当今天与今天的日期匹配时,它应该触发取消功能,但事实并非如此; 有任何想法吗?

松鸦

Dir*_*aws 0

在您的查询中,您可以执行以下操作:

from q in db.Dockets
where q.DocketNum == txtDisplay.Text  
&& q.Status.Equals("CL")  
&& (q.TimeRaised - DateTime.Today).Hours >= 0  
&& !(q.TimeRaised > DateTime.Today.AddDays(1))
select q;
Run Code Online (Sandbox Code Playgroud)

不确定是否可以添加具有未来日期的记录,因此我添加了“ DateTime.Today.AddDays(1) ”逻辑基于比较两个日期返回的 TimeSpan 类:

  TimeSpan ts = DateTime.Now - DateTime.Now.AddYears(-1);
  Console.WriteLine(ts.Days);
Run Code Online (Sandbox Code Playgroud)

这将为您带来 365 天的差异。