mysql(5.1)>使用变量名创建表

jac*_*cob 13 mysql variables dynamic tablename

我正在尝试创建一个基于当前年份和月份(2011-09)的名称的表,但MySQL似乎不喜欢这样.

SET @yyyy_mm=Year(NOW())+'-'+Month(NOW());
CREATE TABLE `survey`.`@yyyy_mm` LIKE `survey`.`interim`;
SHOW TABLES IN `survey`;

+-----------+
| interim   |
+-----------+
| @yyyy_mm  |
+-----------+
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如果我CREATE TABLE;没有勾选@yyyy_mm,我会得到一般语法错误.

@yyyy_mm解决了2020.

nos*_*nos 31

你应该可以做这样的事情:

SET @yyyy_mm=DATE_FORMAT(now(),'%Y-%m');
SET @c = CONCAT('CREATE TABLE `survey`.`',@yyyy_mm, '` LIKE `survey`.`interim`');
PREPARE stmt from @c;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
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Nic*_*ssu 7

set @yyyy_mm=concat(year(now()),'-',month(now()));
set @str = concat('create table survery.`', @yyyy_mm,'` like survey.interim;');
prepare stmt from @str;
execute stmt;
deallocate prepare stmt;
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