C#和Moq,引发在抽象类mock的接口中声明的事件

Question

我正在编写单元测试并在尝试从抽象类mock中引发事件时收到异常.以下是示例代码:

    public abstract class AbstractBase : EntityObject
    {}

    [TestMethod]
    public void MyTest()
    {

        var mock = new Mock<AbstractBase>();
        var notificationMock = entityMock.As<INotifyPropertyChanged>();

        var propertyChangedMapper = new PropertyChangedMapper();

        bool eventReceived = false;
        propertyChangedMapper.MyPropertyChanged +=
            (sender, eventArgs) =>
                {
                    eventReceived = true;
                };

        propertyChangedMapper.Subscribe((AbstractBase)notificationMock.Object);

        Assert.IsFalse(eventReceived);

        notificationMock.Raise(e=>e.PropertyChanged += null, 
                                   new PropertyChangedEventArgs("Property1"));

        Assert.IsTrue(eventReceived);
  }

显然我可以使用mock on INotifyPropertyChanged并且事件上升得很好,但是PropertyChangedMapper我需要将发送者强制转换AbstractBase为失败的Mock<INotifyPropertyChanged>

编辑:根据建议使用Mock.As<>()似乎是正确的方法,上面唯一的问题是,事件的上升notificationMock与对象的原始模拟无关.码:

        notificationMock.Object.PropertyChanged += (s, e) =>
        {
            var result = "this one is fired as it should";
        };

        mock.Object.PropertyChanged += (s, e) =>
        {
            var result = "this one is not called but is actually what I need";
        }; 

        notificationMock.Raise(e => e.PropertyChanged += null, 
                 new PropertyChangedEventArgs("Property1"));

Answer 1

如果您将模拟设为多模拟，您也许能够进行所需的转换。由于 Moq 模拟通过泛型参数绑定到单个类型，因此您必须显式地逐步向模拟添加其他接口或超类，然后在测试中使用最终产品。下面是如何执行此操作的快速示例。

var baseMock = new Mock<AbstractBase>();
var inpcMock = baseMock.As<INotifyPropertyChanged>();

// ...setup event...

propertyChangedMapper.Subscribe(inpcMock.Object);

// ... assertions ...