如何按字母顺序排序而忽略区分大小写？

Question

我有这个代码,但只适用于小写字母.我希望这可以对列表进行排序,同时忽略大写字母..

package sortarray.com;

import java.util.ArrayList;
import java.util.List;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;

public class SortArray extends Activity {
    ArrayList<String[]> matchedFruits = new ArrayList<String[]>();
    TextView selection;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        String fruits[] = new String[7];// Sorted array
        fruits[0] = "apple";
        fruits[1] = "apricot";
        fruits[2] = "banana";
        fruits[3] = "mango";
        fruits[4] = "melon";
        fruits[5] = "pineapple";
        fruits[6] = "peach";
        char currChar = fruits[0].charAt(0);// Get first char of first element

        boolean match = false;
        int len = fruits.length;
        List<String> tmp = new ArrayList<String>();

        for (int i = 1; i < len; i++) {
            Log.d("Comparing ", fruits[i].charAt(0) + "," + currChar);
            if (fruits[i].charAt(0) == currChar) {
                if (match == false)// new match?
                {
                    match = true;// Reset search
                    tmp.clear();// clear existing items
                    tmp.add(fruits[i - 1]);
                    Log.d("Started new list ", fruits[i - 1]);
                } else {
                    tmp.add(fruits[i - 1]);
                    Log.d("Added to list ", fruits[i - 1]);
                }
            } else {
                match = false;
                tmp.add(fruits[i - 1]);
                matchedFruits.add(tmp.toArray(new String[tmp.size()]));// add to
                                                                        // final
                                                                        // list
                Log.d("Finished a list ", fruits[i - 1]);
                tmp.clear();// clear existing items

            }
            currChar = fruits[i].charAt(0);

        }
        tmp.add(fruits[len - 1]);
        matchedFruits.add(tmp.toArray(new String[tmp.size()]));// add left over
                                                                // items
        printList();
    }

    void printList()
    {
    //Print the list 
        TextView selection = (TextView) findViewById(R.id.tv);
        String mssg="";
    for(int i=0;i<matchedFruits.size();i++)
    {
            String tmp2[]= matchedFruits.get(i);

            for (int j = 0; j < tmp2.length; j++) {
                //Log.d("Final list", "Array #" + i + "[" + j + "]," + tmp2[j]);
                mssg += tmp2[j].toString();

            }
            //selection.setText("\n");
            selection.setText(mssg);

    }
    }
}

Answer 1

Collections.sort(listToSort, String.CASE_INSENSITIVE_ORDER);

Answer 2

这是很清楚你正在尝试做的,但你可以排序像这样的列表:

List<String> fruits = new ArrayList<String>(7);

fruits.add("Pineapple");
fruits.add("apple");
fruits.add("apricot");
fruits.add("Banana");
fruits.add("mango");
fruits.add("melon");        
fruits.add("peach");

System.out.println("Unsorted: " + fruits);

Collections.sort(fruits, new Comparator<String>() {
    @Override
    public int compare(String o1, String o2) {              
        return o1.compareToIgnoreCase(o2);
    }
});

System.out.println("Sorted: " + fruits);

Answer 3

这是一个简单的java示例,它是最好的方法:

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;

public class Sorter {
    String fruits[] = new String[7];
    List<String> lst;

    Sorter() {
        lst = new ArrayList<String>();
        // initialise UNSORTED array
        fruits[0] = "Melon"; fruits[1] = "apricot"; fruits[2] = "peach";
        fruits[3] = "mango"; fruits[4] = "Apple";   fruits[5] = "pineapple";
        fruits[6] = "banana";
    }

    public static void main(String[] args) {
        Sorter srt = new Sorter();
        srt.anyOldUnstaticMethod();

    }
    public void anyOldUnstaticMethod() {
        Collections.addAll(lst, fruits);
        System.out.println("Initial List");
        for (String s : lst)
            System.out.println(s);
        Collections.sort(lst);
        System.out.println("\nSorted List");
        for (String s : lst)
            System.out.println(s);
        Collections.sort(lst, new SortIgnoreCase());
        System.out.println("\nSorted Ignoring Case List");
        for (String s : lst)
            System.out.println(s);
    }

    public class SortIgnoreCase implements Comparator<Object> {
        public int compare(Object o1, Object o2) {
            String s1 = (String) o1;
            String s2 = (String) o2;
            return s1.toLowerCase().compareTo(s2.toLowerCase());
        }
    }
}

Answer 4

Collections.sort()允许您传递自定义比较器以进行排序.对于不区分大小写的排序String类,提供了一个静态的最终比较器CASE_INSENSITIVE_ORDER.

所以在你的情况下,所需要的只是:

Collections.sort(caps, String.CASE_INSENSITIVE_ORDER);

Answer 5

我无法相信没有人提到Collat​​or.几乎所有这些答案都只适用于英语.

您应该几乎总是使用Collat​​or进行基于字典的排序.

对于不区分大小写的搜索英语的collat​​or,您可以执行以下操作:

Collator usCollator = Collator.getInstance(Locale.US);
usCollator.setStrength(Collator.PRIMARY);
Collections.sort(listToSort, usCollator);

Answer 6

从 Java 8 开始，您可以使用 Streams API 进行排序：

List<String> fruits = Arrays.asList("apple", "Apricot", "banana");

List<String> sortedFruit = fruits.stream()
      .sorted(String.CASE_INSENSITIVE_ORDER)
      .collect(Collectors.toList())

不同之处Collections.sort在于，这将返回一个新列表，并且不会修改现有列表。

Answer 7

我喜欢比较器类SortIgnoreCase，但会使用它

public class SortIgnoreCase implements Comparator<String> {
    public int compare(String s1, String s2) {
        return s1.compareToIgnoreCase(s2);    // Cleaner :)
    }
}

Answer 8

Java 8 中的数组排序方式-> 简单的柠檬榨汁机

String[] names = {"Alexis", "Tim", "Kyleen", "KRISTY"};

  Arrays.sort(names, String::compareToIgnoreCase);

我使用的方法参考String::compareToIgnoreCase